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You can afford a 
$250 per month car payment. Youve found a 3 year loan at 
5% interest. How big of a loan can you afford?

You can afford a $250 \$ 250 per month car payment. Youve found a 33 year loan at 5% 5 \% interest. How big of a loan can you afford?

Full solution

Q. You can afford a $250 \$ 250 per month car payment. Youve found a 33 year loan at 5% 5 \% interest. How big of a loan can you afford?
  1. Loan Calculation Overview: First, we need to understand that the loan will be paid off in monthly installments over 33 years, which is 3636 months. We also know that the monthly payment is $250\$250 and the annual interest rate is 5%5\%. To find the maximum loan amount, we will use the formula for an installment loan which takes into account the interest rate.
  2. Monthly Payment Formula: The formula for the monthly payment MM for a loan with principal amount PP, monthly interest rate rr, and number of payments nn is:\newlineM=P×r(1+r)n(1+r)n1M = P \times \frac{r(1+r)^n}{(1+r)^n - 1}\newlineWe need to rearrange this formula to solve for PP, the principal amount, which is the maximum loan amount we can afford.
  3. Convert Annual to Monthly Rate: First, we convert the annual interest rate to a monthly interest rate by dividing by 1212, since there are 1212 months in a year.\newlineMonthly interest rate rr = Annual interest rate / 1212\newliner=5%12r = \frac{5\%}{12}\newliner=0.0512r = \frac{0.05}{12}\newliner=0.0041666667r = 0.0041666667
  4. Calculate Number of Payments: Next, we calculate the number of payments nn, which is the number of months in 33 years.n=3 years×12 months/yearn = 3 \text{ years} \times 12 \text{ months/year}n=36 monthsn = 36 \text{ months}
  5. Solve for Principal Amount: Now we can rearrange the formula to solve for PP:P=Mr(1+r)n×[(1+r)n1]P = \frac{M}{r(1+r)^n} \times [(1+r)^n - 1]We will plug in the values for MM, rr, and nn to find PP.
  6. Substitute Values into Formula: Substitute the values into the rearranged formula:\newlineP=250[0.0041666667(1+0.0041666667)36]×[(1+0.0041666667)361]P = \frac{250}{[0.0041666667(1+0.0041666667)^{36}]} \times [(1+0.0041666667)^{36} - 1]\newlineNow we need to calculate the values inside the brackets and then divide 250250 by that result to find PP.
  7. Calculate (1+r)n(1+r)^n: First, calculate (1+r)n(1+r)^n:(1+0.0041666667)36(1+0.0041666667)^{36}This requires using a calculator to raise (1+0.0041666667)(1+0.0041666667) to the power of 3636.
  8. Calculate Denominator: After calculating the above expression, we get: (1+0.0041666667)361.1940523(1+0.0041666667)^{36} \approx 1.1940523
  9. Divide Monthly Payment: Now we calculate the entire denominator of the formula:\newline0.0041666667×1.19405231.19405231\frac{0.0041666667 \times 1.1940523}{1.1940523 - 1}\newlineThis simplifies to:\newline0.00497530.1940523\frac{0.0049753}{0.1940523}
  10. Find Maximum Loan Amount: After calculating the denominator, we get: 0.00497530.19405230.025636\frac{0.0049753}{0.1940523} \approx 0.025636
  11. Find Maximum Loan Amount: After calculating the denominator, we get:\newline0.0049753/0.19405230.0256360.0049753 / 0.1940523 \approx 0.025636Finally, we divide the monthly payment by this result to find the principal amount (PP):\newlineP=2500.025636P = \frac{250}{0.025636}
  12. Find Maximum Loan Amount: After calculating the denominator, we get:\newline0.0049753/0.19405230.0256360.0049753 / 0.1940523 \approx 0.025636Finally, we divide the monthly payment by this result to find the principal amount (PP):\newlineP=2500.025636P = \frac{250}{0.025636}After performing the division, we find the maximum loan amount (PP) that can be afforded:\newlineP9753.47P \approx 9753.47

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