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Yesterday, between noon and midnight, the temperature went down by
28.7^(@)F. If the temperature was
-13.5^(@)F at midnight, what was it at noon?
Answer:
^(@)F

Yesterday, between noon and midnight, the temperature went down by $28.7^{\circ} \mathrm{F}$ . If the temperature was $-13.5^{\circ} \mathrm{F}$ at midnight, what was it at noon? $\newline$ Answer: $\square$ ${ }^{\circ} \mathrm{F}$

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Solve proportions: word problems

Full solution

Q. Yesterday, between noon and midnight, the temperature went down by

28.7^{\circ} \mathrm{F}

. If the temperature was

-13.5^{\circ} \mathrm{F}

at midnight, what was it at noon?

\newline

Answer:

\square

{ }^{\circ} \mathrm{F}

Understand the problem: Understand the problem. $\newline$ We are given the temperature at midnight ( $-13.5\degree\text{F}$ ) and the change in temperature from noon to midnight ( $-28.7\degree\text{F}$ ). We need to find the temperature at noon.
Set up the equation: Set up the equation. $\newline$ Let the temperature at noon be $x$ . The temperature went down by $28.7\degree\text{F}$ , so we subtract this value from the noon temperature to get the midnight temperature. $\newline$ The equation is: $x - 28.7 = -13.5$
Solve for x: Solve for x. $\newline$ Add $28.7$ to both sides of the equation to isolate $x$ on one side. $\newline$ $x - 28.7 + 28.7 = -13.5 + 28.7$ $\newline$ $x = 15.2$
Check the result: Check the result. $\newline$ If the temperature at noon was $15.2\degree\text{F}$ and it went down by $28.7\degree\text{F}$ , then at midnight it would be: $\newline$ $15.2 - 28.7 = -13.5$ $\newline$ This matches the given midnight temperature, so our calculation is correct.

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