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Let’s check out your problem:

y(y+2)=y^(2)-6

y(y+2)=y2−6 y(y+2)=y^{2}-6

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Sin, cos, and tan of special anglesright chevron icon

Full solution

Q. y(y+2)=y2−6 y(y+2)=y^{2}-6
  1. Expand left side: Expand the left side of the equation using the distributive property. y(y+2)=y2+2yy(y+2) = y^2 + 2y
  2. Write right side: Write down the right side of the equation.\newliney2−6y^2 - 6
  3. Set equation: Set the expanded left side equal to the right side to form an equation. y2+2y=y2−6y^2 + 2y = y^2 - 6
  4. Subtract y2y^2: Subtract y2y^2 from both sides to simplify the equation.2y=−62y = -6
  5. Divide by 22: Divide both sides by 22 to solve for yy.y=−62y = \frac{-6}{2}
  6. Calculate y: Calculate the value of yy.y=−3y = -3

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