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y=(x+7)29y=-(x+7)^2-9

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Q. y=(x+7)29y=-(x+7)^2-9
  1. Identify function: Identify the function to differentiate.\newlineWe are given the function y=(x+7)29y = -(x+7)^2 - 9, and we need to find its derivative with respect to xx.
  2. Apply chain rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is u2-u^2 and the inner function is u=x+7u = x + 7.
  3. Differentiate outer function: Differentiate the outer function with respect to the inner function uu. The outer function is u2-u^2. Its derivative with respect to uu is 2u-2u.
  4. Differentiate inner function: Differentiate the inner function with respect to xx. The inner function is u=x+7u = x + 7. Its derivative with respect to xx is 11, since the derivative of xx is 11 and the derivative of a constant is 00.
  5. Apply chain rule multiplication: Apply the chain rule by multiplying the derivatives from Step 33 and Step 44.\newlineThe derivative of yy with respect to xx is the product of the derivative of the outer function and the derivative of the inner function: dydx=2u×1\frac{dy}{dx} = -2u \times 1.
  6. Substitute inner function: Substitute the inner function back into the derivative.\newlineReplace uu with x+7x + 7 in the derivative we found in Step 55: dydx=2(x+7)\frac{dy}{dx} = -2(x + 7).
  7. Simplify derivative: Simplify the derivative.\newlineThe derivative simplifies to dydx=2x14\frac{dy}{dx} = -2x - 14.

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