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Let’s check out your problem:
y
=
(
x
+
5
)
2
y=(x+5)^{2}
y
=
(
x
+
5
)
2
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Math Problems
Precalculus
Factor sums and differences of cubes
Full solution
Q.
y
=
(
x
+
5
)
2
y=(x+5)^{2}
y
=
(
x
+
5
)
2
Use FOIL Method:
To expand
(
x
+
5
)
2
(x + 5)^2
(
x
+
5
)
2
, we'll use the FOIL method, which stands for First, Outer, Inner, Last.
First Term:
First: Multiply the first terms in each binomial,
x
×
x
=
x
2
x \times x = x^2
x
×
x
=
x
2
.
Outer Terms:
Outer: Multiply the outer terms,
x
×
5
=
5
x
x \times 5 = 5x
x
×
5
=
5
x
.
Inner Terms:
Inner: Multiply the inner terms,
5
×
x
=
5
x
5 \times x = 5x
5
×
x
=
5
x
.
Last Term:
Last: Multiply the last terms in each binomial,
5
×
5
=
25
5 \times 5 = 25
5
×
5
=
25
.
Add Products:
Now, add all the products together:
x
2
+
5
x
+
5
x
+
25
x^2 + 5x + 5x + 25
x
2
+
5
x
+
5
x
+
25
.
Combine Like Terms:
Combine like terms:
x
2
+
10
x
+
25
x^2 + 10x + 25
x
2
+
10
x
+
25
.
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−
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x =
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