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y=x2+7x5y=x^2+7x-5 make xx the subject

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Q. y=x2+7x5y=x^2+7x-5 make xx the subject
  1. Move constant term: To isolate xx, we need to complete the square. First, move the constant term to the other side of the equation by adding 55 to both sides.\newliney+5=x2+7xy + 5 = x^2 + 7x
  2. Complete the square: Now, to complete the square, we need to add and subtract (b2)2(\frac{b}{2})^2, where bb is the coefficient of xx. In this case, b=7b = 7, so (72)2=494(\frac{7}{2})^2 = \frac{49}{4}.y+5+494=x2+7x+494y + 5 + \frac{49}{4} = x^2 + 7x + \frac{49}{4}
  3. Subtract 494\frac{49}{4}: Subtract 494\frac{49}{4} from both sides to keep the equation balanced.\newliney+5494=x2+7x+494494y + 5 - \frac{49}{4} = x^2 + 7x + \frac{49}{4} - \frac{49}{4}
  4. Simplify left side: Simplify the left side of the equation. y+204494=(x+72)2y + \frac{20}{4} - \frac{49}{4} = (x + \frac{7}{2})^2
  5. Combine terms: Combine the terms on the left side. y294=(x+72)2y - \frac{29}{4} = (x + \frac{7}{2})^2
  6. Take square root: Take the square root of both sides to solve for xx.±y294=x+72\pm\sqrt{y - \frac{29}{4}} = x + \frac{7}{2}
  7. Subtract 72\frac{7}{2}: Subtract 72\frac{7}{2} from both sides to isolate xx.\newlinex=±y29472x = \pm\sqrt{y - \frac{29}{4}} - \frac{7}{2}

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