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y=(x-1)^(2)

y=(x1)2y=(x-1)^{2}

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Q. y=(x1)2y=(x-1)^{2}
  1. Identify Function and Rule: Identify the function and the rule needed for differentiation.\newlineWe have y=(x1)2y = (x-1)^2, which is a basic power function.\newlineUsing the power rule for differentiation, where if y=uny = u^n, then y=nu(n1)uy' = n\cdot u^{(n-1)}\cdot u'.
  2. Differentiate Inside Function: Differentiate the inside function u=x1u = x-1. Differentiating u=x1u = x-1 gives us u=1u' = 1.
  3. Apply Chain Rule: Apply the chain rule.\newlineUsing the power rule and the result from the previous step, the derivative y=2(x1)211y' = 2\cdot(x-1)^{2-1}\cdot1.\newlineSimplify to get y=2(x1)y' = 2\cdot(x-1).

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