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y=5x+2

4x-y=0
Is 
(2,12) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

y=5x+2 y=5 x+2 \newline4xy=0 4 x-y=0 \newlineIs (2,12) (2,12) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. y=5x+2 y=5 x+2 \newline4xy=0 4 x-y=0 \newlineIs (2,12) (2,12) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and Check First Equation: First, we will substitute the point (2,12)(2,12) into the first equation and check if it holds true. The first equation is y=5x+2y = 5x + 2. If we substitute x=2x=2 and y=12y=12, we get 12=5×2+212 = 5 \times 2 + 2.
  2. Verify First Equation: After performing the calculation, we find that 12=10+212 = 10 + 2, which simplifies to 12=1212 = 12. This is true, so the point (2,12)(2,12) satisfies the first equation.
  3. Substitute and Check Second Equation: Next, we will substitute the point (2,12)(2,12) into the second equation and check if it holds true. The second equation is 4xy=04x - y = 0. If we substitute x=2x=2 and y=12y=12, we get 4212=04\cdot 2 - 12 = 0.
  4. Verify Second Equation: After performing the calculation, we find that 812=48 - 12 = -4, which is not equal to 00. Therefore, the point (2,12)(2,12) does not satisfy the second equation.
  5. Solution to the System of Equations: Since the point (2,12)(2,12) does not satisfy both equations, it is not a solution to the system of equations.

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