y=3x-5 y=x-1 Is (2,1) a solution of the system? Choose 1 answer: (A) Yes (B) No

Substitute and Check First Equation: First, we will substitute the point (2,1) into the first equation and check if it holds true. The first equation is y = 3x - 5. If we substitute x=2 and y=1, we get 1 = 3*2 - 5. Substitute and Check Second Equation: After performing the calculation, we find that 1 = 6 - 5, which simplifies to 1 = 1, which is true. Therefore, the point (2,1) satisfies the first equation. Point (2,1) Satisfies Both Equations: Next, we will substitute the point (2,1) into the second equation and check if it holds true. The second equation is y = x - 1. If we substitute x=2 and y=1, we get 1 = 2 - 1. After performing the calculation, we find that 1 = 1, which is also true. Therefore, the point (2,1) satisfies the second equation as well. Since the point (2,1) satisfies both equations, it is a solution to the system of equations.

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y=3x-5

y=x-1
Is
(2,1) a solution of the system?
Choose 1 answer:
(A) Yes
(B)
No

$y=3 x-5$ $\newline$ $y=x-1$ $\newline$ Is $(2,1)$ a solution of the system? $\newline$ Choose $1$ answer: $\newline$ (A) Yes $\newline$ (B) No

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

y=3 x-5

\newline

y=x-1

\newline

(2,1)

a solution of the system?

\newline

Choose

1

answer:

\newline

(A) Yes

\newline

(B) No

Substitute and Check First Equation: First, we will substitute the point $(2,1)$ into the first equation and check if it holds true. The first equation is $y = 3x - 5$ . If we substitute $x=2$ and $y=1$ , we get $1 = 3 \times 2 - 5$ .
Substitute and Check Second Equation: After performing the calculation, we find that $1 = 6 - 5$ , which simplifies to $1 = 1$ , which is true. Therefore, the point $(2,1)$ satisfies the first equation.
Point $(2,1)$ Satisfies Both Equations: Next, we will substitute the point $(2,1)$ into the second equation and check if it holds true. The second equation is y = x - 1 \. If we substitute \$ x=2 and $y=1$ , we get \(1 = $2$ - $1$ \.
Point $(2,1)$ Satisfies Both Equations: Next, we will substitute the point $(2,1)$ into the second equation and check if it holds true. The second equation is $y = x - 1$ . If we substitute $x=2$ and $y=1$ , we get $1 = 2 - 1$ . After performing the calculation, we find that $1 = 1$ , which is also true. Therefore, the point $(2,1)$ satisfies the second equation as well.
Point $(2,1)$ Satisfies Both Equations: Next, we will substitute the point $(2,1)$ into the second equation and check if it holds true. The second equation is $y = x - 1$ . If we substitute $x=2$ and $y=1$ , we get $1 = 2 - 1$ . After performing the calculation, we find that $1 = 1$ , which is also true. Therefore, the point $(2,1)$ satisfies the second equation as well. Since the point $(2,1)$ satisfies both equations, it is a solution to the system of equations.