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y=-(3)/(4)x+1

x

y

-4

0

4

$y=-\frac{3}{4} x+1$ $\newline$ \begin{tabular}{|l|l|} $\newline$ \hline $x$ & $y$ \\ $\newline$ \hline $-4$ & \\ $\newline$ \hline $0$ & \\ $\newline$ \hline $4$ & \\ $\newline$ \hline $\newline$ \end{tabular}

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Add and subtract rational numbers

Full solution

Q.

y=-\frac{3}{4} x+1

\newline

\begin{tabular}{|l|l|}

\newline

\hline

x

&

y

\\

\newline

\hline

-4

& \\

\newline

\hline

0

& \\

\newline

\hline

4

& \\

\newline

\hline

\newline

\end{tabular}

Substitute $x = -4$ : To find $y$ when $x$ is $-4$ , plug in $x = -4$ into the equation $y = -\frac{3}{4}x + 1$ . $\newline$ $y = -\frac{3}{4}(-4) + 1$ $\newline$ $y = 3 + 1$ $\newline$ $y = 4$
Substitute $x = 0$ : To find $y$ when $x$ is $0$ , plug in $x = 0$ into the equation $y = -\frac{3}{4}x + 1$ . $\newline$ $y = -\frac{3}{4}(0) + 1$ $\newline$ $y = 0 + 1$ $\newline$ $y = 1$
Substitute $x = 4$ : To find $y$ when $x$ is $4$ , plug in $x = 4$ into the equation $y = -\frac{3}{4}x + 1$ . $\newline$ $y = -\frac{3}{4}(4) + 1$ $\newline$ $y = -3 + 1$ $\newline$ $y = -2$

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