Q. y=2x−15x−4y=1Is (1,1) a solution of the system?Choose 1 answer:(A) Yes(B) No
Substitute and check first equation: First, we will substitute the point (1,1) into the first equation and check if it holds true. The first equation is y=2x−1. If we substitute x=1 and y=1, we get 1=2⋅1−1.
Verify first equation holds true: After performing the calculation, we find that 1=2−1, which simplifies to 1=1, which is true. Therefore, the point (1,1) satisfies the first equation.
Substitute and check second equation: Next, we will substitute the point (1,1) into the second equation and check if it holds true. The second equation is 5x−4y=1. If we substitute x=1 and y=1, we get 5⋅1−4⋅1=1.
Verify second equation holds true: After performing the calculation, we find that 5−4=1, which is also true. Therefore, the point (1,1) satisfies the second equation as well.
Solution satisfies both equations: Since the point (1,1) satisfies both equations, it is a solution to the system of equations.
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