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x+y=1x+y=1 , y+z=1y+z=-1 and z+x=2z+x=2. \newlineWhat is the value of xyzx-y-z

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Q. x+y=1x+y=1 , y+z=1y+z=-1 and z+x=2z+x=2. \newlineWhat is the value of xyzx-y-z
  1. Identify Equations: Identify the system of equations:\newlinex+y=1x + y = 1\newliney+z=1y + z = -1\newlinez+x=2z + x = 2
  2. Solve for x: Solve for x using the first and third equations:\newlinex+y=1x + y = 1\newlinez+x=2z + x = 2\newlineSubtract the first from the third:\newlinez+x(x+y)=21z + x - (x + y) = 2 - 1\newlinezy=1z - y = 1
  3. Solve for zz: Solve for zz using the second equation:\newliney+z=1y + z = -1\newlineSubstitute zy=1z - y = 1 into this equation:\newliney+(1+y)=1y + (1 + y) = -1\newline2y+1=12y + 1 = -1\newline2y=22y = -2\newliney=1y = -1
  4. Find x: Find x using y=1y = -1 in the first equation:\newlinex+(1)=1x + (-1) = 1\newlinex1=1x - 1 = 1\newlinex=2x = 2
  5. Find zz: Find zz using y=1y = -1 in the second equation:\newline1+z=1-1 + z = -1\newlinez=0z = 0
  6. Calculate xyzx - y - z: Calculate xyzx - y - z:xyz=2(1)0x - y - z = 2 - (-1) - 0xyz=3x - y - z = 3

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