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XX is a normally distributed random variable with mean 3838 and standard deviation 44. What is the probability that XX is between 2626 and 5050? Use the 0.680.950.9970.68-0.95-0.997 rule and write your answer as a decimal. Round to the nearest thousandth if necessary.

Full solution

Q. XX is a normally distributed random variable with mean 3838 and standard deviation 44. What is the probability that XX is between 2626 and 5050? Use the 0.680.950.9970.68-0.95-0.997 rule and write your answer as a decimal. Round to the nearest thousandth if necessary.
  1. Calculate z-score for X=26X=26: Mean (μ\mu) is 3838 and standard deviation (σ\sigma) is 44. Calculate the z-score for X=26X=26.\newlineZ=Xμσ=26384=124=3Z = \frac{X - \mu}{\sigma} = \frac{26 - 38}{4} = \frac{-12}{4} = -3.
  2. Calculate z-score for X=50X=50: Calculate the z-score for X=50X=50.Z=Xμσ=50384=124=3Z = \frac{X - \mu}{\sigma} = \frac{50 - 38}{4} = \frac{12}{4} = 3.
  3. Identify probability range for z-scores: Using the 0.680.68-0.950.95-0.9970.997 rule, identify the probability range for the z-scores.\newlineA z-score of 3-3 to 33 covers almost all the data, which corresponds to approximately 0.9970.997 of the data.
  4. Calculate probability for XX between 2626 and 5050: The probability that XX is between 2626 and 5050 is about 0.9970.997.

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