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x^(4)-13x^(2)+40

55) x413x2+40 x^{4}-13 x^{2}+40

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Q. 55) x413x2+40 x^{4}-13 x^{2}+40
  1. Factor Quadratic Equation: Let's factor the equation like a quadratic, where x2x^2 is our variable.\newlinex413x2+40=0x^4 - 13x^2 + 40 = 0\newlineThink of it as (x2)213(x2)+40=0(x^2)^2 - 13(x^2) + 40 = 0\newlineNow, factor it.\newline(x25)(x28)=0(x^2 - 5)(x^2 - 8) = 0
  2. Set Equal and Solve: Set each factor equal to zero and solve for x2x^2.\newlinex25=0x^2 - 5 = 0 and x28=0x^2 - 8 = 0\newlineSo, x2=5x^2 = 5 and x2=8x^2 = 8
  3. Take Square Root: Now, take the square root of both sides for each equation.\newlineFor x2=5x^2 = 5, we get x=±5x = \pm\sqrt{5}.\newlineFor x2=8x^2 = 8, we get x=±8x = \pm\sqrt{8}, but 8\sqrt{8} can be simplified to 222\sqrt{2}.\newlineSo, x=±22x = \pm2\sqrt{2}.

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