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x
3
6
9
12



y
12
10
8
6

\begin{tabular}{|c|c|c|c|c|}\newline\hlinex x & 33 & 66 & 99 & 1212 \\\newline\hliney y & 1212 & 1010 & 88 & 66 \\\newline\hline\newline\end{tabular}

Full solution

Q. \begin{tabular}{|c|c|c|c|c|}\newline\hlinex x & 33 & 66 & 99 & 1212 \\\newline\hliney y & 1212 & 1010 & 88 & 66 \\\newline\hline\newline\end{tabular}
  1. Check Pattern: Check if there's a pattern between xx and yy values.\newlinexx: 33, 66, 99, 1212\newlineyy: 1212, 1010, yy00, 66\newlineLooks like as xx increases, yy decreases.
  2. Find Differences: Let's find the difference between consecutive yy values.y2y1=1012=2y_2 - y_1 = 10 - 12 = -2y3y2=810=2y_3 - y_2 = 8 - 10 = -2y4y3=68=2y_4 - y_3 = 6 - 8 = -2The difference is constant, so it might be a linear relationship.
  3. Constant Relationship: Now, let's find the difference between consecutive xx values.x2x1=63=3x_2 - x_1 = 6 - 3 = 3x3x2=96=3x_3 - x_2 = 9 - 6 = 3x4x3=129=3x_4 - x_3 = 12 - 9 = 3The difference is also constant.
  4. Calculate Slope: Try to find the slope mm of the line that represents the relationship.m=y2y1x2x1=23m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2}{3}So, the slope is 23-\frac{2}{3}.
  5. Find Y-Intercept: Use the slope and one point to find the y-intercept bb of the line.\newlineLet's use point (3,12)(3, 12).\newliney=mx+by = mx + b\newline12=(2/3)×3+b12 = (-2/3)\times 3 + b\newline12=2+b12 = -2 + b\newlineb=12+2b = 12 + 2\newlineb=14b = 14
  6. Write Equation: Write the equation of the line using the slope and y-intercept.\newliney=mx+by = mx + b\newliney=23x+14y = -\frac{2}{3}x + 14

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