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x=(((1)/(2))/(2+2))/((2+2+2)/((2+2+2)/(2)))

x=122+22+2+22+2+22 x=\frac{\frac{\frac{1}{2}}{2+2}}{\frac{2+2+2}{\frac{2+2+2}{2}}}

Full solution

Q. x=122+22+2+22+2+22 x=\frac{\frac{\frac{1}{2}}{2+2}}{\frac{2+2+2}{\frac{2+2+2}{2}}}
  1. Simplify numerator: Step 11: Simplify the numerator.\newlineWe start by simplifying the innermost parentheses in the numerator.\newlineCalculation: (12)/(2+2)=(12)/4=18(\frac{1}{2}) / (2 + 2) = (\frac{1}{2}) / 4 = \frac{1}{8}
  2. Simplify denominator: Step 22: Simplify the denominator.\newlineNext, simplify the denominator by handling the inner division first.\newlineCalculation: (2+2+2)/((2+2+2)/2)=6/(6/2)=6/3=2(2 + 2 + 2) / ((2 + 2 + 2) / 2) = 6 / (6 / 2) = 6 / 3 = 2
  3. Divide numerator by denominator: Step 33: Divide the simplified numerator by the simplified denominator.\newlineNow, divide the results from Step 11 and Step 22.\newlineCalculation: (18)/2=1812=116(\frac{1}{8}) / 2 = \frac{1}{8} * \frac{1}{2} = \frac{1}{16}

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