www-awualekscom/alelscgi/X/slexe/to_u-lgNsikasNW8D8A9PVVie IcCraphs and functionsWord problom involving composition of two functionsThe braking distance D(v) (in meters) for a certain car moving at velocity v (in meters/second) is given by D(v)=22v2The car's velocity B(t) (in meters/second) t seconds after starting is given by B(t)=9t.Write a formula for the braking distance S(t) (in meters) after t seconds.
Q. www-awualekscom/alelscgi/X/slexe/to_u-lgNsikasNW8D8A9PVVie IcCraphs and functionsWord problom involving composition of two functionsThe braking distance D(v) (in meters) for a certain car moving at velocity v (in meters/second) is given by D(v)=22v2The car's velocity B(t) (in meters/second) t seconds after starting is given by B(t)=9t.Write a formula for the braking distance S(t) (in meters) after t seconds.
Identify Functions: Identify the functions given and the function to be found.We have D(v)=22v2 for braking distance based on velocity, and B(t)=9t for velocity based on time. We need to find S(t), the braking distance as a function of time.
Substitute and Find: Substitute the expression for B(t) into D(v) to find S(t).Since D(v)=22v2 and B(t)=9t, substituting B(t) into D(v) gives:S(t)=22(9t)2
Simplify Expression: Simplify the expression for S(t). S(t)=2281t2This is the formula for the braking distance in meters after t seconds.
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