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Write the log equation as an exponential equation. You do not need to solve for
x.

log(x^(2)+3x-6)=2
Answer:

Write the log equation as an exponential equation. You do not need to solve for $\mathrm{x}$ . $\newline$ $\log \left(x^{2}+3 x-6\right)=2$ $\newline$ Answer:

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Convert between exponential and logarithmic form: all bases

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for

\mathrm{x}

.

\newline

\log \left(x^{2}+3 x-6\right)=2

\newline

Answer:

Identify base, exponent, result: Identify the base $b$ , the exponent $y$ , and the result $x$ in the logarithmic equation $\log(x^{2}+3x-6)=2$ . In a logarithmic equation of the form $\log_b(x) = y$ , $b$ is the base, $x$ is the result, and $y$ is the exponent. Here, the base is understood to be $10$ because it is not written, so $b = 10$ , $y$ $0$ , and the result is the expression $y$ $1$ .
Convert to exponential form: Convert the logarithmic equation to its equivalent exponential form using the relationship $b^y = x$ . Substitute $b = 10$ and $y = 2$ into the equation to get $10^2 = x^2+3x-6$ .
Write final exponential equation: Write the final exponential equation. $\newline$ The exponential form of the given logarithmic equation $\log(x^{2}+3x-6)=2$ is $10^{2} = x^{2}+3x-6$ .

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