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Write the log equation as an exponential equation. You do not need to solve for x. log_(2x)(4x+2)=2x+3 Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog⁡2x(4x+2)=2x+3 \log _{2 x}(4 x+2)=2 x+3 \newlineAnswer:

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Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog⁡2x(4x+2)=2x+3 \log _{2 x}(4 x+2)=2 x+3 \newlineAnswer:
  1. Define logarithmic equation: The question_prompt: ＂What is the exponential form of the logarithmic equation log⁡2x(4x+2)=2x+3\log_{2x}(4x+2) = 2x+3?＂\newlineTo convert a logarithmic equation to an exponential equation, we use the definition of a logarithm: if log⁡b(a)=c\log_b(a) = c, then bc=ab^c = a.
  2. Convert to exponential form: Using the definition of a logarithm, we can rewrite the given logarithmic equation log⁡2x(4x+2)=2x+3\log_{2x}(4x+2) = 2x+3 as an exponential equation. The base is (2x)(2x), the exponent is the right side of the equation (2x+3)(2x+3), and the result is the argument of the log (4x+2)(4x+2). So, the exponential form is (2x)2x+3=4x+2(2x)^{2x+3} = 4x+2.

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