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Write the log equation as an exponential equation. You do not need to solve for 
x.

log_(5x)(5x)=2
Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog5x(5x)=2 \log _{5 x}(5 x)=2 \newlineAnswer:

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog5x(5x)=2 \log _{5 x}(5 x)=2 \newlineAnswer:
  1. Question Prompt: The question_prompt: Convert the logarithmic equation to an exponential equation.
  2. Logarithmic Equation: We have the logarithmic equation: log5x(5x)=2\log_{5x}(5x) = 2. To convert this to an exponential equation, we use the definition of a logarithm. The definition states that if logb(a)=c\log_b(a) = c, then bc=ab^c = a.
  3. Definition of Logarithm: Using the definition, we can rewrite log5x(5x)=2\log_{5x}(5x) = 2 as an exponential equation where the base is (5x)(5x), the exponent is 22, and the result is the argument of the logarithm, which is also (5x)(5x).
  4. Exponential Equation: Therefore, the exponential form of the equation is \(5x)^22 = 55x\

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