Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write the equation of the line that passes through the points (-6,-1) and (8,4). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line. Answer:

Write the equation of the line that passes through the points (−6,−1) (-6,-1) and (8,4) (8,4) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 8right chevron icon
Write a linear equation from two pointsright chevron icon

Full solution

Q. Write the equation of the line that passes through the points (−6,−1) (-6,-1) and (8,4) (8,4) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:
  1. Calculate slope: Calculate the slope mm of the line using the formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1} with the given points (−6,−1)(-6,-1) and (8,4)(8,4).
    m=4−(−1)8−(−6)m = \frac{4 - (-1)}{8 - (-6)}
    m=4+18+6m = \frac{4 + 1}{8 + 6}
    m=514m = \frac{5}{14}
  2. Choose point: Choose one of the points to use in the point-slope form equation. We will use the point (−6,−1)(-6,-1).
  3. Write point-slope equation: Write the equation of the line in point-slope form using the slope m=514m = \frac{5}{14} and the point (−6,−1)(-6,-1). The point-slope form is y−y1=m(x−x1)y - y_1 = m(x - x_1).\newliney−(−1)=(514)(x−(−6))y - (-1) = \left(\frac{5}{14}\right)(x - (-6))\newliney+1=(514)(x+6)y + 1 = \left(\frac{5}{14}\right)(x + 6)
  4. Simplify equation: Simplify the equation by distributing the slope on the right side.\newliney+1=514x+514⋅6y + 1 = \frac{5}{14}x + \frac{5}{14}\cdot6\newliney+1=514x+3014y + 1 = \frac{5}{14}x + \frac{30}{14}\newliney+1=514x+157y + 1 = \frac{5}{14}x + \frac{15}{7}
  5. Subtract 11: Subtract 11 from both sides to get the final point-slope form of the equation.\newliney=514x+157−1y = \frac{5}{14}x + \frac{15}{7} - 1\newliney=514x+157−77y = \frac{5}{14}x + \frac{15}{7} - \frac{7}{7}\newliney=514x+87y = \frac{5}{14}x + \frac{8}{7}

More problems from Write a linear equation from two points

Question
Does the point (0,4)(0, 4) satisfy the equation y=xy = x??\newlineChoices: [[yes]][[no]]
Get tutor helpright-arrow

Posted 2 months ago

Question
Find the slope of the line y=−4x+25 y = -4x + \frac{2}{5} .\newlineWrite your answer as an integer or as a simplified proper or improper fraction.
Get tutor helpright-arrow

Posted 1 month ago

Question
Rewrite the following equation in slope-intercept form.\newliney+8=−8(x−10)y + 8 = -8(x - 10)\newlineWrite your answer using integers, proper fractions, and improper fractions in simplest form.\newline_____
Get tutor helpright-arrow

Posted 1 month ago

Question
Find the y y -intercept of the line 14x−16y=−10 14x - 16y = -10 .\newlineWrite your answer as an integer or as a simplified proper or improper fraction, not as an ordered pair.\newline____
Get tutor helpright-arrow

Posted 1 month ago

Question
Line q q has a slope of −23 \frac{-2}{3} . Line r r is perpendicular to q q . What is the slope of line r r ?\newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____\_\_\_\_\_
Get tutor helpright-arrow

Posted 1 month ago

Question
Find the slope of the line y+3=−118(x+6)y + 3 = -\frac{1}{18}(x + 6).\newlineWrite your answer as an integer or as a simplified proper or improper fraction.
Get tutor helpright-arrow

Posted 1 month ago

Question
Line p p has an equation of y=−8x+6 y = -8x + 6 . Line q q , which is perpendicular to line p p , includes the point (2,−2) (2, -2) . What is the equation of line q q ??\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.\newline____
Get tutor helpright-arrow

Posted 1 month ago

Question
Is the graph of this equation a horizontal or vertical line?\newlinex=7x = 7\newlineChoices:\newline(A)horizontal line\text{(A)horizontal line}\newline(B)vertical line\text{(B)vertical line}
Get tutor helpright-arrow

Posted 2 months ago

Question
Rewrite the following equation in standard form.\newliney=−10x+7 y = -10x + 7 \newlineHint: The standard form of a linear equation is\newlineAx+By=C Ax + By = C where A A and B B are not both zero, and A A , B B , and C C are integers whose GCF is 11. ______
Get tutor helpright-arrow

Posted 2 months ago

Question
A line with a slope of 99 passes through the point (9,9)(9,9). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\hspace{1cm}} = \underline{\hspace{1cm}} (x - \underline{\hspace{1cm}})
Get tutor helpright-arrow

Posted 1 month ago

View all (64)