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Write an integral expression that will give the length of the path given by f(x)=10x41 f(x) = 10x^4 - 1 from x=7 x = 7 to x=8 x = 8 .

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Q. Write an integral expression that will give the length of the path given by f(x)=10x41 f(x) = 10x^4 - 1 from x=7 x = 7 to x=8 x = 8 .
  1. Set Up Integral for Arc Length: To find the length of the path described by the function f(x)=10x41f(x) = 10x^4 - 1 from x=7x = 7 to x=8x = 8, we need to set up the integral for arc length in one dimension. The formula for the arc length of a function f(x)f(x) from aa to bb is given by the integral from aa to bb of the square root of 11 plus the derivative of f(x)f(x) squared, x=7x = 700.
  2. Find Derivative of Function: First, we need to find the derivative of the function f(x)=10x41f(x) = 10x^4 - 1. The derivative, f(x)f'(x), is found using the power rule for differentiation.\newlinef(x)=ddx[10x41]=40x3.f'(x) = \frac{d}{dx} [10x^4 - 1] = 40x^3.
  3. Square the Derivative: Next, we square the derivative to include it in the arc length formula.\newline(f'(x))^\(2 = (4040x^33)^22 = 16001600x^66\.
  4. Write Integral Expression: Now, we can write the integral expression for the arc length. The integral expression is the integral from 77 to 88 of the square root of 1+(f(x))21 + (f'(x))^2 dx.\newlineSo, the integral expression is 781+1600x6dx\int_{7}^{8} \sqrt{1 + 1600x^6} \, dx.
  5. Evaluate Integral for Length: This integral expression represents the length of the path of the function f(x)f(x) from x=7x = 7 to x=8x = 8. To find the actual length, one would need to evaluate this integral, which may require numerical methods or approximation techniques as it does not have a simple antiderivative.

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