Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write an exponential function to model the situation. Then solve.
The cost of tuition at a college is 
$12,000 and is increasing at a rate of 
6% per year. What will the cost be after 4 years?

{:[C(t)=12000(1.06)^(t)"; "],[C(t)=12000(.06)^(t)"; "],[C(t)=12000(.06)^(t)"; "],[C(t)=12000(1.06)^(t)"; "],[$3149.72],[$1472.95],[$3149.72]:}

Write an exponential function to model the situation. Then solve.\newlineThe cost of tuition at a college is $12,000 \$ 12,000 and is increasing at a rate of 6% 6 \% per year. What will the cost be after 44 years?\newlineC(t)=12000(1.06)tC(t)=12000(.06)tC(t)=12000(.06)tC(t)=12000(1.06)t$3149.72$1472.95$3149.72 \begin{array}{l} C(t)=12000(1.06)^{t} \text {; } \\ C(t)=12000(.06)^{t} \text {; } \\ C(t)=12000(.06)^{t} \text {; } \\ C(t)=12000(1.06)^{t} \text {; } \\ \$ 3149.72 \\ \$ 1472.95 \\ \$ 3149.72 \\ \end{array}

Full solution

Q. Write an exponential function to model the situation. Then solve.\newlineThe cost of tuition at a college is $12,000 \$ 12,000 and is increasing at a rate of 6% 6 \% per year. What will the cost be after 44 years?\newlineC(t)=12000(1.06)tC(t)=12000(.06)tC(t)=12000(.06)tC(t)=12000(1.06)t$3149.72$1472.95$3149.72 \begin{array}{l} C(t)=12000(1.06)^{t} \text {; } \\ C(t)=12000(.06)^{t} \text {; } \\ C(t)=12000(.06)^{t} \text {; } \\ C(t)=12000(1.06)^{t} \text {; } \\ \$ 3149.72 \\ \$ 1472.95 \\ \$ 3149.72 \\ \end{array}
  1. Identify Function Type: Identify the type of function to model the situation.\newlineSince the cost of tuition is increasing at a percentage rate per year, this is an exponential growth situation.
  2. Write Exponential Function: Write the exponential function to model the situation.\newlineThe general form of an exponential growth function is C(t)=a(1+r)tC(t) = a(1 + r)^t, where:\newline- C(t)C(t) is the cost after tt years,\newline- aa is the initial amount,\newline- rr is the growth rate (expressed as a decimal),\newline- tt is the time in years.\newlineGiven a=$12,000a = \$12,000 and r=6%r = 6\% or 0.060.06, the function is C(t)=12000(1.06)tC(t) = 12000(1.06)^t.
  3. Calculate Tuition Cost: Calculate the cost of tuition after 44 years.\newlineSubstitute t=4t = 4 into the function C(t)=12000(1.06)tC(t) = 12000(1.06)^t to find C(4)C(4).\newlineC(4)=12000(1.06)4C(4) = 12000(1.06)^4
  4. Perform Calculation: Perform the calculation for C(4)C(4).C(4)=12000(1.06)4C(4) = 12000(1.06)^4C(4)=12000×(1.262476)C(4) = 12000 \times (1.262476)C(4)=15149.712C(4) = 15149.712
  5. Round to Nearest Cent: Round the result to the nearest cent, if necessary.\newlineThe cost of tuition after 44 years is $15,149.71\$15,149.71 when rounded to the nearest cent.

More problems from Write linear and exponential functions: word problems