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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineFinn works in an amusement park and is helping decorate it with strands of lights. This morning, he used a total of 6060 strands of lights to decorate 55 bushes and 33 trees. This afternoon, he strung lights on 55 bushes and 22 trees, using a total of 5050 strands. Assuming that all bushes are decorated one way and all trees are decorated another, how many strands did Finn use on each?\newlineFinn decorated every bush with ___\_\_\_ strands of lights and every tree with ___\_\_\_ strands.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineFinn works in an amusement park and is helping decorate it with strands of lights. This morning, he used a total of 6060 strands of lights to decorate 55 bushes and 33 trees. This afternoon, he strung lights on 55 bushes and 22 trees, using a total of 5050 strands. Assuming that all bushes are decorated one way and all trees are decorated another, how many strands did Finn use on each?\newlineFinn decorated every bush with ___\_\_\_ strands of lights and every tree with ___\_\_\_ strands.
  1. Define variables: Let's define variables for the number of strands used per bush and per tree.\newlineLet b=b = number of strands per bush\newlineLet t=t = number of strands per tree
  2. Write first equation: Write the first equation based on the morning decoration.\newline55 bushes and 33 trees use 6060 strands.\newline5b+3t=605b + 3t = 60
  3. Write second equation: Write the second equation based on the afternoon decoration.\newline55 bushes and 22 trees use 5050 strands.\newline5b+2t=505b + 2t = 50
  4. Elimination method: Solve the system of equations using the substitution or elimination method. We will use the elimination method.\newlineTo eliminate one of the variables, we can multiply the second equation by 1.5-1.5 and add it to the first equation.\newline1.5(5b+2t)=1.5(50)-1.5(5b + 2t) = -1.5(50)\newline7.5b3t=75-7.5b - 3t = -75\newlineNow add this to the first equation:\newline5b+3t=605b + 3t = 60\newline7.5b3t=75-7.5b - 3t = -75\newline-----------------\newline2.5b=15-2.5b = -15
  5. Solve for b: Solve for b.\newline2.5b=15-2.5b = -15\newlineDivide both sides by 2.5-2.5 to find b.\newlineb=152.5b = \frac{-15}{-2.5}\newlineb=6b = 6
  6. Substitute to solve for t: Substitute the value of bb back into one of the original equations to solve for tt. Using the second equation: 5b+2t=505b + 2t = 50 5(6)+2t=505(6) + 2t = 50 30+2t=5030 + 2t = 50 2t=50302t = 50 - 30 2t=202t = 20 Divide both sides by 22 to find tt. t=202t = \frac{20}{2} tt00

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