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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineBaldwin and Gavin, both teachers, are adding books to their class libraries. Baldwin's classroom started out with a collection of only 77 books, but he plans to purchase an additional 22 books per week. Gavin's library started out with 99 books, and he has enough money in his budget to purchase another 11 book per week. At some point, the two teachers' libraries will contain the same number of books. How many weeks will that take? How many books will each class have?\newlineAfter _\_ weeks, the two teachers' libraries will each have _\_ books.

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Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineBaldwin and Gavin, both teachers, are adding books to their class libraries. Baldwin's classroom started out with a collection of only 77 books, but he plans to purchase an additional 22 books per week. Gavin's library started out with 99 books, and he has enough money in his budget to purchase another 11 book per week. At some point, the two teachers' libraries will contain the same number of books. How many weeks will that take? How many books will each class have?\newlineAfter _\_ weeks, the two teachers' libraries will each have _\_ books.
  1. Define Variables: Let's define the variables:\newlineLet BB represent the total number of books in Baldwin's library.\newlineLet GG represent the total number of books in Gavin's library.\newlineLet ww represent the number of weeks that have passed.\newlineWe can write two equations to represent the situation:\newlineFor Baldwin: B=7+2wB = 7 + 2w (since he starts with 77 books and adds 22 each week)\newlineFor Gavin: G=9+wG = 9 + w (since he starts with 99 books and adds 11 each week)\newlineWe want to find the value of ww when BB equals GG.
  2. Set Up Equations: Now we set up the system of equations:\newline11) B=7+2wB = 7 + 2w\newline22) G=9+wG = 9 + w\newlineSince we are looking for when BB equals GG, we can set the two equations equal to each other:\newline7+2w=9+w7 + 2w = 9 + w
  3. Solve for w: Next, we solve for w using substitution or elimination. In this case, we can simply subtract ww from both sides to isolate ww:7+2ww=9+ww7 + 2w - w = 9 + w - wThis simplifies to:7+w=97 + w = 9
  4. Determine Books After 22 Weeks: Now we solve for ww: \newline7+w=97 + w = 9\newlineSubtract 77 from both sides:\newlinew=97w = 9 - 7\newlinew=2w = 2
  5. Check Solution: We have found that after 22 weeks, the two teachers' libraries will have the same number of books. Now we need to determine how many books each class will have.\newlineWe can substitute ww back into either original equation. Let's use Baldwin's equation:\newlineB=7+2wB = 7 + 2w\newlineB=7+2(2)B = 7 + 2(2)\newlineB=7+4B = 7 + 4\newlineB=11B = 11
  6. Check Solution: We have found that after 22 weeks, the two teachers' libraries will have the same number of books. Now we need to determine how many books each class will have.\newlineWe can substitute ww back into either original equation. Let's use Baldwin's equation:\newlineB=7+2wB = 7 + 2w\newlineB=7+2(2)B = 7 + 2(2)\newlineB=7+4B = 7 + 4\newlineB=11B = 11To check our work, we should also substitute ww into Gavin's equation to ensure it gives us the same number of books:\newlineG=9+wG = 9 + w\newlineG=9+2G = 9 + 2\newline$G = \(11\)
  7. Check Solution: We have found that after \(2\) weeks, the two teachers' libraries will have the same number of books. Now we need to determine how many books each class will have.\(\newline\)We can substitute \(w\) back into either original equation. Let's use Baldwin's equation:\(\newline\)\(B = 7 + 2w\)\(\newline\)\(B = 7 + 2(2)\)\(\newline\)\(B = 7 + 4\)\(\newline\)\(B = 11\)To check our work, we should also substitute \(w\) into Gavin's equation to ensure it gives us the same number of books:\(\newline\)\(G = 9 + w\)\(\newline\)\(G = 9 + 2\)\(\newline\)\(G = 11\)Both Baldwin and Gavin will have \(w\)\(0\) books in their libraries after \(2\) weeks. This confirms our solution is correct.

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