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Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineThe Ashland High School Science Department is purchasing new earth science and physics textbooks this year. Ms. Walton has requested 8080 earth science textbooks and 9292 physics textbooks for all of her classes, which costs the department a total of $7,744\$7,744. Mr. Castro has asked for 8080 earth science textbooks and 7676 physics textbooks, which will cost a total of $6,912\$6,912. How much do the textbooks cost?\newlineEarth science textbooks cost $\$____ apiece and physics textbooks cost $\$____ apiece.

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Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.\newlineThe Ashland High School Science Department is purchasing new earth science and physics textbooks this year. Ms. Walton has requested 8080 earth science textbooks and 9292 physics textbooks for all of her classes, which costs the department a total of $7,744\$7,744. Mr. Castro has asked for 8080 earth science textbooks and 7676 physics textbooks, which will cost a total of $6,912\$6,912. How much do the textbooks cost?\newlineEarth science textbooks cost $\$____ apiece and physics textbooks cost $\$____ apiece.
  1. Define Costs: Let's denote the cost of one earth science textbook as xx dollars and the cost of one physics textbook as yy dollars. We can write two equations based on the information given:\newlineFor Ms. Walton's request: 8080 earth science textbooks and 9292 physics textbooks cost a total of $7,744\$7,744.\newlineFor Mr. Castro's request: 8080 earth science textbooks and 7676 physics textbooks cost a total of $6,912\$6,912.
  2. Write Equations: Translate the information into a system of equations:\newlineMs. Walton's order: 80x+92y=7,74480x + 92y = 7,744\newlineMr. Castro's order: 80x+76y=6,91280x + 76y = 6,912
  3. Eliminate Variable: To use elimination, we need to eliminate one of the variables. Since the coefficient of xx is the same in both equations, we can eliminate xx by subtracting the second equation from the first.\newline(80x+92y)(80x+76y)=7,7446,912(80x + 92y) - (80x + 76y) = 7,744 - 6,912
  4. Subtract Equations: Perform the subtraction to find the value of yy:80x+92y80x76y=7,7446,91280x + 92y - 80x - 76y = 7,744 - 6,91292y76y=7,7446,91292y - 76y = 7,744 - 6,91216y=83216y = 832y=83216y = \frac{832}{16}y=52y = 52
  5. Find y Value: Now that we have the value of yy, we can substitute it back into one of the original equations to find the value of xx. Let's use Ms. Walton's order:\newline80x+92(52)=7,74480x + 92(52) = 7,744
  6. Substitute y: Calculate the value of xx:80x+4,784=7,74480x + 4,784 = 7,74480x=7,7444,78480x = 7,744 - 4,78480x=2,96080x = 2,960x=2,96080x = \frac{2,960}{80}x=37x = 37
  7. Calculate xx: We have found the values of xx and yy, which represent the cost of earth science and physics textbooks, respectively:\newlinex=37x = 37 (cost of one earth science textbook)\newliney=52y = 52 (cost of one physics textbook)

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