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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineThis morning, Ben processed two catering orders at the sandwich shop where he works. The first order was for 77 trays of club sandwiches and 55 trays of vegetarian sandwiches, at a cost of $103\$103. The second order, which cost $53\$53, was for 55 trays of club sandwiches and 11 tray of vegetarian sandwiches. How much do the trays cost?\newlineA tray of club sandwiches costs $\$_____, and a tray of vegetarian sandwiches costs $\$_____.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineThis morning, Ben processed two catering orders at the sandwich shop where he works. The first order was for 77 trays of club sandwiches and 55 trays of vegetarian sandwiches, at a cost of $103\$103. The second order, which cost $53\$53, was for 55 trays of club sandwiches and 11 tray of vegetarian sandwiches. How much do the trays cost?\newlineA tray of club sandwiches costs $\$_____, and a tray of vegetarian sandwiches costs $\$_____.
  1. Cost Equations: Let's denote the cost of a tray of club sandwiches as xx dollars and the cost of a tray of vegetarian sandwiches as yy dollars. The first order's cost equation can be written as:\newline7x+5y=1037x + 5y = 103
  2. System of Equations: The second order's cost equation can be written as: 5x+1y=535x + 1y = 53
  3. Elimination Method: We now have a system of equations to solve:\newline7x+5y=1037x + 5y = 103\newline5x+y=535x + y = 53\newlineWe can use either substitution or elimination to solve this system. Let's use the elimination method.
  4. Solving for x: To eliminate yy, we can multiply the second equation by 5-5 and add it to the first equation:\newline5(5x+y)=5(53)-5(5x + y) = -5(53)\newline25x5y=265-25x - 5y = -265\newlineNow we add this to the first equation:\newline7x+5y=1037x + 5y = 103\newline25x5y=265-25x - 5y = -265\newline-----------------\newline18x=162-18x = -162
  5. Substitute x: Solving for x, we divide both sides by 18-18:\newline18x/18=162/18-18x / -18 = -162 / -18\newlinex=9x = 9
  6. Solving for y: Now that we have the value for xx, we can substitute it back into one of the original equations to solve for yy. Let's use the second equation:\newline5x+y=535x + y = 53\newline5(9)+y=535(9) + y = 53\newline45+y=5345 + y = 53
  7. Solving for y: Now that we have the value for xx, we can substitute it back into one of the original equations to solve for yy. Let's use the second equation:\newline5x+y=535x + y = 53\newline5(9)+y=535(9) + y = 53\newline45+y=5345 + y = 53Solving for yy, we subtract 4545 from both sides:\newliney=5345y = 53 - 45\newliney=8y = 8

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