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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineJanelle and Bridget both plan to run for a spot on the school board in their city. They must each collect a certain number of signatures to get their name on the ballot. So far, Janelle has 1515 signatures, but Bridget just started and doesn't have any yet. Janelle is collecting signatures at an average rate of 55 per hour, while Bridget can get 2020 signatures every hour. Assuming that their rate of collection stays the same, eventually the two will have collected the same number of signatures. How many hours will have gone by? How many signatures will they both have?\newlineIn \underline{\hspace{2cm}} hours, Janelle and Bridget will each have collected \underline{\hspace{2cm}}.

Full solution

Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineJanelle and Bridget both plan to run for a spot on the school board in their city. They must each collect a certain number of signatures to get their name on the ballot. So far, Janelle has 1515 signatures, but Bridget just started and doesn't have any yet. Janelle is collecting signatures at an average rate of 55 per hour, while Bridget can get 2020 signatures every hour. Assuming that their rate of collection stays the same, eventually the two will have collected the same number of signatures. How many hours will have gone by? How many signatures will they both have?\newlineIn \underline{\hspace{2cm}} hours, Janelle and Bridget will each have collected \underline{\hspace{2cm}}.
  1. Define Variables: Let's define the variables:\newlineLet JJ represent the total number of signatures Janelle will have.\newlineLet BB represent the total number of signatures Bridget will have.\newlineLet hh represent the number of hours that have gone by.
  2. Write Equations: We can write two equations to represent the situation:\newlineFor Janelle: J=15+5hJ = 15 + 5h (since she starts with 1515 and collects 55 per hour)\newlineFor Bridget: B=20hB = 20h (since she starts with 00 and collects 2020 per hour)
  3. Set Equations Equal: Since we are looking for the point where Janelle and Bridget have the same number of signatures, we set the two equations equal to each other:\newline15+5h=20h15 + 5h = 20h
  4. Solve for hh: Now we solve for hh by subtracting 5h5h from both sides of the equation:\newline15+5h5h=20h5h15 + 5h - 5h = 20h - 5h\newline15=15h15 = 15h
  5. Divide and Solve: Next, we divide both sides by 1515 to solve for hh:1515=15h15\frac{15}{15} = \frac{15h}{15}1=h1 = h
  6. Substitute and Find: Now that we know h=1h = 1, we can find out how many signatures they will each have by substituting hh back into either J's or B's equation. Let's use Janelle's equation:\newlineJ=15+5(1)J = 15 + 5(1)\newlineJ=15+5J = 15 + 5\newlineJ=20J = 20
  7. Final Signatures: Since we know that Janelle and Bridget will have the same number of signatures, Bridget will also have 2020 signatures after 11 hour.

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