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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineMrs. Warren, the P.E. teacher, is pairing off students to race against each other. Colton can run 55 yards per second, and Eduardo can run 99 yards per second. Mrs. Warren decides to give Colton a head start of 88 yards since he runs more slowly. Once the students start running, Eduardo will quickly catch up to Colton. How far will Eduardo have to run? How long will that take?\newlineEduardo will catch up to Colton after running _\_ yards in _\_ seconds.

Full solution

Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineMrs. Warren, the P.E. teacher, is pairing off students to race against each other. Colton can run 55 yards per second, and Eduardo can run 99 yards per second. Mrs. Warren decides to give Colton a head start of 88 yards since he runs more slowly. Once the students start running, Eduardo will quickly catch up to Colton. How far will Eduardo have to run? How long will that take?\newlineEduardo will catch up to Colton after running _\_ yards in _\_ seconds.
  1. Define Variables: Let's define the variables for the distances that Colton and Eduardo run as C C and E E respectively, and let t t represent the time in seconds after they start running. We can write two equations based on the information given:\newline11. Colton's distance equation: Since Colton gets an 88-yard head start and runs at 55 yards per second, his distance can be represented as C=5t+8 C = 5t + 8 .\newline22. Eduardo's distance equation: Eduardo runs at 99 yards per second, so his distance can be represented as E=9t E = 9t .\newlineWe want to find out when Eduardo catches up to Colton, which means C=E C = E . So we can set the two equations equal to each other to solve for t t :\newline5t+8=9t 5t + 8 = 9t
  2. Equations Setup: Now we will solve for t t using substitution:\newline5t+8=9t 5t + 8 = 9t \newlineSubtract 5t 5t from both sides to get:\newline8=4t 8 = 4t \newlineNow divide both sides by 44 to solve for t t :\newlinet=2 t = 2
  3. Solve for t: Now that we have the time it takes for Eduardo to catch up to Colton, we can find out how far Eduardo will have to run. We use Eduardo's distance equation:\newlineE=9t E = 9t \newlineE=9×2 E = 9 \times 2 \newlineE=18 E = 18 \newlineSo, Eduardo will have to run 1818 yards to catch up to Colton.
  4. Find Eduardo's Distance: Finally, we check if our solution makes sense. Colton has an 88-yard head start and runs at 55 yards per second. In 22 seconds, he will have run:\newlineC=5t+8 C = 5t + 8 \newlineC=5×2+8 C = 5 \times 2 + 8 \newlineC=10+8 C = 10 + 8 \newlineC=18 C = 18 \newlineBoth Colton and Eduardo have run 1818 yards after 22 seconds, which confirms that Eduardo catches up to Colton after running 1818 yards in 22 seconds.

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