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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineRon is a server at an all-you-can eat sushi restaurant. At one table, the customers ordered 22 child buffets and 22 adult buffets, which cost a total of $82\$82. At another table, the customers ordered 22 child buffets and 33 adult buffets, paying a total of $108\$108. How much does the buffet cost for each child and adult?\newlineThe cost for a child is $\$_____, and the cost for an adult is $\$_____.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineRon is a server at an all-you-can eat sushi restaurant. At one table, the customers ordered 22 child buffets and 22 adult buffets, which cost a total of $82\$82. At another table, the customers ordered 22 child buffets and 33 adult buffets, paying a total of $108\$108. How much does the buffet cost for each child and adult?\newlineThe cost for a child is $\$_____, and the cost for an adult is $\$_____.
  1. Define Buffet Costs: Let's denote the cost of the child buffet as cc and the cost of the adult buffet as aa. We need to find the values of cc and aa.
  2. First Table's Order: From the first table's order, we have the equation for the total cost of 22 child buffets and 22 adult buffets:\newline2c+2a=$(82)2c + 2a = \$(82)
  3. Second Table's Order: From the second table's order, we have the equation for the total cost of 22 child buffets and 33 adult buffets:\newline2c+3a=$(108)2c + 3a = \$(108)
  4. System of Equations: We now have a system of equations:\newline2c+2a=$(82)2c + 2a = \$(82)\newline2c+3a=$(108)2c + 3a = \$(108)\newlineWe can solve this system using the method of elimination or substitution. Let's use elimination.
  5. Elimination Method: Subtract the first equation from the second equation to eliminate "c":\newline(2c+3a)(2c+2a)=($)108($)82(2c + 3a) - (2c + 2a) = (\$)108 - (\$)82\newline3a2a=($)263a - 2a = (\$)26\newlinea=($)26a = (\$)26
  6. Find Cost of Adult Buffet: Now that we have the value of aa, we can substitute it back into one of the original equations to find cc. Let's use the first equation:\newline2c+2(26)=($)822c + 2(26) = (\$)82\newline2c+($)52=($)822c + (\$)52 = (\$)82\newline2c=($)82($)522c = (\$)82 - (\$)52\newline2c=($)302c = (\$)30\newlinec=($)15c = (\$)15

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