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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo tailors, Harper and Rachel, sit down to do some embroidery. Harper can embroider 44 shirts per hour, and Rachel can get through 66 shirts per hour. In addition, the tailors had previously finished some shirts. Harper has already completed 2121 shirts, and Rachel has completed 55 shirts. Harper and Rachel decide to take a break when they have finished the same total number of shirts. How long will that take? How many shirts, in total, will each tailor have finished?\newlineIn \underline{\quad} hours, each tailor will have finished a total of \underline{\quad} shirts.

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Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo tailors, Harper and Rachel, sit down to do some embroidery. Harper can embroider 44 shirts per hour, and Rachel can get through 66 shirts per hour. In addition, the tailors had previously finished some shirts. Harper has already completed 2121 shirts, and Rachel has completed 55 shirts. Harper and Rachel decide to take a break when they have finished the same total number of shirts. How long will that take? How many shirts, in total, will each tailor have finished?\newlineIn \underline{\quad} hours, each tailor will have finished a total of \underline{\quad} shirts.
  1. Equation for Harper: We know:\newlineHarper's embroidery rate: 44 shirts/hour\newlineHarper's initial shirts: 2121\newlineWhat is the equation for Harper's total shirts embroidered over time?\newlineTotal shirts embroidered = (Embroidery rate ×\times Time) + Initial shirts\newlineLet xx represent the number of hours and yy represent the total number of shirts embroidered.\newlineFor Harper: y=(4×x)+21y = (4 \times x) + 21
  2. Equation for Rachel: We know:\newlineRachel's embroidery rate: 66 shirts/hour\newlineRachel's initial shirts: 55\newlineWhat is the equation for Rachel's total shirts embroidered over time?\newlineTotal shirts embroidered = (Embroidery rate ×\times Time) + Initial shirts\newlineFor Rachel: y=(6×x)+5y = (6 \times x) + 5
  3. Substitution to Solve: We have:\newlineShirts embroidered by Harper: y=4x+21y = 4x + 21\newlineShirts embroidered by Rachel: y=6x+5y = 6x + 5\newlineUse substitution to solve for xx.\newlineSet the two equations equal to each other since they will have embroidered the same number of shirts:\newline4x+21=6x+54x + 21 = 6x + 5
  4. Solving for x: Now, solve for x:\newline4x+21=6x+54x + 21 = 6x + 5\newlineSubtract 4x4x from both sides:\newline21=2x+521 = 2x + 5\newlineSubtract 55 from both sides:\newline16=2x16 = 2x\newlineDivide both sides by 22:\newlinex=8x = 8
  5. Value of y: We have:\newliney = 44x + 2121\newlineWhat is the value of y when x=8x = 8?\newliney = 44(88) + 2121\newliney = 3232 + 2121\newliney = 5353
  6. Final Solution: We have:\newlinex=8x = 8\newliney=53y = 53\newlineHow long did it take for them to embroider the same number of shirts?\newlineAnd how many shirts had each of them completed?\newlineTime: 88 hours\newlineNumber of shirts = 5353\newlineIn 88 hours, each tailor will have finished a total of 5353 shirts.

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