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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Sandra can read 33 pages per minute, while Ronald can read 22 pages per minute. When they met, Sandra had already read 2121 pages, and Ronald had already gotten through 5050 pages. After a while, they had both read the same number of pages. How long did that take? How many pages had each one read?\newlineAfter ___\_\_\_ minutes, Sandra and Ronald had each read ___\_\_\_ pages.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Sandra can read 33 pages per minute, while Ronald can read 22 pages per minute. When they met, Sandra had already read 2121 pages, and Ronald had already gotten through 5050 pages. After a while, they had both read the same number of pages. How long did that take? How many pages had each one read?\newlineAfter ___\_\_\_ minutes, Sandra and Ronald had each read ___\_\_\_ pages.
  1. Define Reading Rates: Let's denote the time they both read together as tt (in minutes). Sandra's reading rate is 33 pages per minute, and Ronald's is 22 pages per minute. Sandra had a head start of 2121 pages, and Ronald had a head start of 5050 pages.
  2. Write Equations: We can write the equation for the total number of pages Sandra has read as: Total pages Sandra read = 3t+213t + 21.
  3. Set Equations Equal: Similarly, the equation for the total number of pages Ronald has read is: Total pages Ronald read = 2t+502t + 50.
  4. Solve for Time: Since they have read the same number of pages after tt minutes, we can set the two equations equal to each other: 3t+21=2t+503t + 21 = 2t + 50.
  5. Calculate Pages Read: Now, we solve for tt by subtracting 2t2t from both sides: 3t2t+21=2t2t+503t - 2t + 21 = 2t - 2t + 50, which simplifies to t+21=50t + 21 = 50.
  6. Final Result: Subtracting 2121 from both sides gives us t=5021t = 50 - 21, which means t=29t = 29.
  7. Final Result: Subtracting 2121 from both sides gives us t=5021t = 50 - 21, which means t=29t = 29.Now that we have the time, we can calculate the total number of pages each has read. For Sandra: 3×29+21=87+21=1083 \times 29 + 21 = 87 + 21 = 108 pages.
  8. Final Result: Subtracting 2121 from both sides gives us t=5021t = 50 - 21, which means t=29t = 29. Now that we have the time, we can calculate the total number of pages each has read. For Sandra: 3×29+21=87+21=1083 \times 29 + 21 = 87 + 21 = 108 pages. For Ronald: 2×29+50=58+50=1082 \times 29 + 50 = 58 + 50 = 108 pages.
  9. Final Result: Subtracting 2121 from both sides gives us t=5021t = 50 - 21, which means t=29t = 29. Now that we have the time, we can calculate the total number of pages each has read. For Sandra: 3×29+21=87+21=1083 \times 29 + 21 = 87 + 21 = 108 pages. For Ronald: 2×29+50=58+50=1082 \times 29 + 50 = 58 + 50 = 108 pages. Therefore, after 2929 minutes, Sandra and Ronald had each read 108108 pages.

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