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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo groups of volunteers are cleaning up the football stadium after the Homecoming game. Volunteers from the Band Booster Club have already cleaned 1212 rows of bleachers and will continue to clean at a rate of 77 rows per minute. The leadership class has completed 66 rows and will continue working at 88 rows per minute. Once the two groups get to the point where they have cleaned the same number of rows, they will take a break and decide how to split up the remaining work. How long will that take? How many minutes will each group have cleaned by then?\newlineIn _\_ minutes, the groups will each cleaned _\_ rows each.

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Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo groups of volunteers are cleaning up the football stadium after the Homecoming game. Volunteers from the Band Booster Club have already cleaned 1212 rows of bleachers and will continue to clean at a rate of 77 rows per minute. The leadership class has completed 66 rows and will continue working at 88 rows per minute. Once the two groups get to the point where they have cleaned the same number of rows, they will take a break and decide how to split up the remaining work. How long will that take? How many minutes will each group have cleaned by then?\newlineIn _\_ minutes, the groups will each cleaned _\_ rows each.
  1. Define Variables: Let's define the variables:\newlineLet xx be the number of minutes both groups will work until they have cleaned the same number of rows.\newlineLet yy be the total number of rows cleaned by each group when they take a break.\newlineBand Booster Club's rate of cleaning is 77 rows per minute, and they have already cleaned 1212 rows.\newlineThe equation for the Band Booster Club is:\newliney=7x+12y = 7x + 12
  2. Band Booster Club: The leadership class's rate of cleaning is 88 rows per minute, and they have already cleaned 66 rows.\newlineThe equation for the leadership class is:\newliney=8x+6y = 8x + 6
  3. Leadership Class: Now we have two equations:\newline11) y=7x+12y = 7x + 12 (Band Booster Club)\newline22) y=8x+6y = 8x + 6 (Leadership class)\newlineWe can use substitution to find the value of xx by setting the two equations equal to each other since yy represents the same total number of rows cleaned by each group at the time they take a break.\newline7x+12=8x+67x + 12 = 8x + 6
  4. Substitution: Solving for xx:7x+12=8x+67x + 12 = 8x + 6Subtract 7x7x from both sides:12=x+612 = x + 6Subtract 66 from both sides:x=126x = 12 - 6x=6x = 6
  5. Solving for x: Now that we have the value of xx, we can substitute it back into either of the original equations to find yy. Let's use the first equation:\newliney=7x+12y = 7x + 12\newliney=7(6)+12y = 7(6) + 12\newliney=42+12y = 42 + 12\newliney=54y = 54

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