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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Leo can read 11 page per minute, while Shawna can read 33 pages per minute. When they met, Leo had already read 7575 pages, and Shawna had already gotten through 1919 pages. After a while, they had both read the same number of pages. How many pages had each one read? How long did that take?\newlineLeo and Shawna had each read _\_ pages after _\_ minutes.

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Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Leo can read 11 page per minute, while Shawna can read 33 pages per minute. When they met, Leo had already read 7575 pages, and Shawna had already gotten through 1919 pages. After a while, they had both read the same number of pages. How many pages had each one read? How long did that take?\newlineLeo and Shawna had each read _\_ pages after _\_ minutes.
  1. Define Variables: Let's define the variables:\newlineLet xx be the number of minutes they read together.\newlineLet LL be the total number of pages Leo read.\newlineLet SS be the total number of pages Shawna read.\newlineWe can write two equations based on the given information:\newlineFor Leo: L=75+1×xL = 75 + 1 \times x (since Leo reads 11 page per minute and had already read 7575 pages)\newlineFor Shawna: S=19+3×xS = 19 + 3 \times x (since Shawna reads 33 pages per minute and had already read 1919 pages)\newlineWe are also told that after a while, they had both read the same number of pages, which gives us the equation:\newlineL=SL = S
  2. Write Equations: Now we can set up the system of equations:\newline11. L=75+xL = 75 + x\newline22. S=19+3xS = 19 + 3x\newlineAnd since L=SL = S, we can substitute the expression for LL from the first equation into the second equation:\newline75+x=19+3x75 + x = 19 + 3x
  3. Set Up System: Next, we solve for xx:75+x=19+3x75 + x = 19 + 3xSubtract xx from both sides:75=19+2x75 = 19 + 2xSubtract 1919 from both sides:56=2x56 = 2xDivide both sides by 22:x=28x = 28
  4. Solve for x: Now that we have the value of xx, we can find the total number of pages each person read. We'll substitute xx back into the equations for LL and SS:
    For Leo: L=75+x=75+28=103L = 75 + x = 75 + 28 = 103 pages
    For Shawna: S=19+3x=19+3×28=19+84=103S = 19 + 3x = 19 + 3\times28 = 19 + 84 = 103 pages
  5. Find Total Pages: We have found that both Leo and Shawna read 103103 pages each after 2828 minutes.

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