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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Sophie can read 11 page per minute, while Quincy can read 44 pages per minute. When they met, Sophie had already read 8383 pages, and Quincy had already gotten through 1111 pages. After a while, they had both read the same number of pages. How many pages had each one read? How long did that take?\newlineSophie and Quincy had each read _\_ pages after _\_ minutes.

Full solution

Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates got together over the weekend to do their assigned History reading. Sophie can read 11 page per minute, while Quincy can read 44 pages per minute. When they met, Sophie had already read 8383 pages, and Quincy had already gotten through 1111 pages. After a while, they had both read the same number of pages. How many pages had each one read? How long did that take?\newlineSophie and Quincy had each read _\_ pages after _\_ minutes.
  1. Define Variables: Let's define the variables for the system of equations. Let xx represent the number of minutes they read together, and let SS represent the total number of pages Sophie has read, and QQ represent the total number of pages Quincy has read.\newlineSophie's rate is 11 page per minute, and she had already read 8383 pages. So, her equation will be:\newlineS=1×x+83S = 1 \times x + 83\newlineQuincy's rate is 44 pages per minute, and he had already read 1111 pages. So, his equation will be:\newlineQ=4×x+11Q = 4 \times x + 11\newlineWe are given that after a while, they had both read the same number of pages, which means S=QS = Q.
  2. Set Up Equations: Now we set up the system of equations using the information we have:\newline11. S=x+83S = x + 83\newline22. Q=4x+11Q = 4x + 11\newlineAnd since S=QS = Q, we can write:\newlinex+83=4x+11x + 83 = 4x + 11
  3. Solve for x: Next, we solve for x using substitution. We already have S=QS = Q, so we can substitute SS for QQ in the second equation:\newlinex+83=4x+11x + 83 = 4x + 11\newlineNow, we solve for x by getting all the x terms on one side and the constants on the other:\newlinex4x=1183x - 4x = 11 - 83\newline3x=72-3x = -72
  4. Find Total Time: Divide both sides by 3-3 to find the value of xx:3x3=723\frac{-3x}{-3} = \frac{-72}{-3}x=24x = 24This means they read together for 2424 minutes.
  5. Find Sophie's Pages: Now that we have the value of xx, we can find out how many pages each person read. We'll substitute xx back into one of the original equations. Let's use Sophie's equation:\newlineS=x+83S = x + 83\newlineS=24+83S = 24 + 83\newlineS=107S = 107\newlineSo, Sophie read 107107 pages in total.
  6. Check Quincy's Pages: We can also check Quincy's total pages read to ensure our solution is consistent:\newlineQ=4x+11Q = 4x + 11\newlineQ=4×24+11Q = 4 \times 24 + 11\newlineQ=96+11Q = 96 + 11\newlineQ=107Q = 107\newlineQuincy also read 107107 pages in total, which confirms our solution is correct.

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