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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates, Billy and Evelyn, plan to meet in the computer lab to type up their research papers. Billy can type at a speed of 11 page per hour, whereas Evelyn can type 33 pages per hour. So far, Billy already has 1414 pages typed up, compared to Evelyn's 44 pages. Once they sit down and start typing together, the two students will reach the same page count before too long. How long will that take? What will the page count be?\newlineAfter _\_ hours, each student will have a page count of _\_ pages.

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Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineTwo classmates, Billy and Evelyn, plan to meet in the computer lab to type up their research papers. Billy can type at a speed of 11 page per hour, whereas Evelyn can type 33 pages per hour. So far, Billy already has 1414 pages typed up, compared to Evelyn's 44 pages. Once they sit down and start typing together, the two students will reach the same page count before too long. How long will that take? What will the page count be?\newlineAfter _\_ hours, each student will have a page count of _\_ pages.
  1. Define Variables: Let's define the variables:\newlineLet xx be the number of hours they type in the computer lab.\newlineLet yy be the total number of pages each student has after xx hours.\newlineBilly's typing rate is 11 page per hour, and he starts with 1414 pages. So, the equation for Billy's total pages after xx hours is:\newliney=1×x+14y = 1 \times x + 14\newliney=x+14y = x + 14
  2. Billy's Equation: Evelyn's typing rate is 33 pages per hour, and she starts with 44 pages. So, the equation for Evelyn's total pages after xx hours is:\newliney=3×x+4y = 3 \times x + 4
  3. Evelyn's Equation: Now we have two equations:\newline11. y=x+14y = x + 14 (Billy's equation)\newline22. y=3x+4y = 3x + 4 (Evelyn's equation)\newlineSince we are looking for the point where they have the same number of pages, we can set the two equations equal to each other and solve for xx:\newlinex+14=3x+4x + 14 = 3x + 4
  4. Set Equations Equal: Subtract xx from both sides to get the xx terms on one side:\newlinex+14x=3x+4xx + 14 - x = 3x + 4 - x\newline14=2x+414 = 2x + 4
  5. Solve for x: Subtract 44 from both sides to isolate the term with xx:\newline144=2x+4414 - 4 = 2x + 4 - 4\newline10=2x10 = 2x
  6. Substitute xx: Divide both sides by 22 to solve for xx:102=2x2\frac{10}{2} = \frac{2x}{2}5=x5 = x
  7. Final Result: Now that we have the value of xx, we can substitute it back into either equation to find yy. Let's use Billy's equation:\newliney=x+14y = x + 14\newliney=5+14y = 5 + 14\newliney=19y = 19
  8. Final Result: Now that we have the value of xx, we can substitute it back into either equation to find yy. Let's use Billy's equation:\newliney=x+14y = x + 14\newliney=5+14y = 5 + 14\newliney=19y = 19We have found that after 55 hours, each student will have a page count of 1919 pages.

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