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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineManuel often orders party trays from his favorite Mexican food restaurant for company events. For a recent company party, he spent $34\$34 on 11 burrito platter. For a company meeting, he spent $123\$123 on 33 burrito platters and 11 taco platter. How much does each type of platter cost?\newlineEach burrito platter costs $____\$\_\_\_\_ and each taco platter costs $____\$\_\_\_\_.

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Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineManuel often orders party trays from his favorite Mexican food restaurant for company events. For a recent company party, he spent $34\$34 on 11 burrito platter. For a company meeting, he spent $123\$123 on 33 burrito platters and 11 taco platter. How much does each type of platter cost?\newlineEach burrito platter costs $____\$\_\_\_\_ and each taco platter costs $____\$\_\_\_\_.
  1. Define Variables: Let's call the cost of a burrito platter bb and the cost of a taco platter tt. We can write two equations based on the given information:\newline11 burrito platter = $34\$34, so b=34b = 34.\newline33 burrito platters + 11 taco platter = $123\$123, so 3b+t=1233b + t = 123.
  2. Write Equations: Now we'll write the system of equations as an augmented matrix:\newline\begin{array}{cc|c} 1 & 0 & 34 \ 3 & 1 & 123 \ \end{array}
  3. Create Augmented Matrix: To solve the system using an augmented matrix, we'll use row operations to get the matrix into reduced row-echelon form (RREF). First, we'll make sure the first row is our pivot row since it already has a leading 11.
  4. Perform Row Operations: Next, we'll use the pivot row to eliminate the 33 in the second row. We'll multiply the first row by 3-3 and add it to the second row:\newline3×(10 34)+(31 123)=(01 21)-3 \times \begin{pmatrix} 1 & 0 \ 34 & \end{pmatrix} + \begin{pmatrix} 3 & 1 \ 123 & \end{pmatrix} = \begin{pmatrix} 0 & 1 \ 21 & \end{pmatrix}\newlineThis gives us the new second row.

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