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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineIn a paint factory, an old conveyer line has filled 1010 barrels of paint, and is filling more at a rate of 11 barrel per minute. A worker just switched on a newer line that can fill 66 barrels per minute. In a little while, the two lines will have filled an equal number of barrels. How many barrels will each line have filled? How long will that take?\newlineBoth lines will have filled _\_ barrels in _\_ minutes.

Full solution

Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineIn a paint factory, an old conveyer line has filled 1010 barrels of paint, and is filling more at a rate of 11 barrel per minute. A worker just switched on a newer line that can fill 66 barrels per minute. In a little while, the two lines will have filled an equal number of barrels. How many barrels will each line have filled? How long will that take?\newlineBoth lines will have filled _\_ barrels in _\_ minutes.
  1. Define Variables: Let's define the variables: Let x x be the number of minutes after the newer line starts. The old line has already filled 1010 barrels and continues to fill at a rate of 11 barrel per minute. The newer line fills at a rate of 66 barrels per minute.
  2. Write Equations: Write the equations for each line: \newlineFor the old line: y=10+x y = 10 + x (since it starts with 1010 barrels and fills 11 more each minute).\newlineFor the new line: y=6x y = 6x (since it starts from 00 and fills 66 barrels per minute).
  3. Set Equations Equal: Set the equations equal to solve for x x : \newline10+x=6x 10 + x = 6x .\newlineRearrange to solve for x x : \newline10=5x 10 = 5x .\newlinex=2 x = 2 minutes.
  4. Substitute and Solve: Substitute x=2 x = 2 back into either equation to find y y :\newlineUsing y=6x y = 6x : \newliney=6(2)=12 y = 6(2) = 12 barrels.

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