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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineAt an ice cream store, a family ordered 11 banana split, paying a total of $6\$6 for their order. The next customer ordered 44 banana splits and 66 hot fudge sundaes and paid $54\$54. How much does each item cost?\newlineA banana split costs $____\$\_\_\_\_ and a hot fudge sundae costs $_____\$\_\_\_\_\_.

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Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineAt an ice cream store, a family ordered 11 banana split, paying a total of $6\$6 for their order. The next customer ordered 44 banana splits and 66 hot fudge sundaes and paid $54\$54. How much does each item cost?\newlineA banana split costs $____\$\_\_\_\_ and a hot fudge sundae costs $_____\$\_\_\_\_\_.
  1. Define Variables: Let xx be the cost of a banana split and yy be the cost of a hot fudge sundae.\newlineFirst family's order: 11 banana split (xx) for $6\$6.\newline1x+0y=61x + 0y = 6
  2. First Family's Order: Next customer's order: 44 banana splits (x)(x) and 66 hot fudge sundaes (y)(y) for $54\$54.4x+6y=544x + 6y = 54
  3. Next Customer's Order: Create an augmented matrix to represent the system of equations:\newline\begin{array}{cc|c} 1 & 0 & 6 \ 4 & 6 & 54 \ \end{array}
  4. Create Augmented Matrix: Use row operations to find the cost of each item.\newlineFirst, multiply the first row by 4-4 and add it to the second row to eliminate xx from the second equation.\newline4×10 466 54+4654=4654+4024=0630-4 \times \left| \begin{array}{cc} 1 & 0 \ 4 & 6 \end{array} \right| \begin{array}{c} 6 \ 54 \end{array} + \left| \begin{array}{cc} 4 & 6 \end{array} \right| \begin{array}{c} 54 \end{array} = \left| \begin{array}{cc} 4 & 6 \end{array} \right| \begin{array}{c} 54 \end{array} + \left| \begin{array}{cc} -4 & 0 \end{array} \right| \begin{array}{c} -24 \end{array} = \left| \begin{array}{cc} 0 & 6 \end{array} \right| \begin{array}{c} 30 \end{array}
  5. Use Row Operations: Now we have the new system of equations:\newline1x+0y=61x + 0y = 6\newline0x+6y=300x + 6y = 30
  6. New System of Equations: Solve for yy by dividing the second equation by 66.6y6=306\frac{6y}{6} = \frac{30}{6}y=5y = 5
  7. Solve for yy: Substitute y=5y = 5 into the first equation to solve for xx.1x+0(5)=61x + 0(5) = 6x=6x = 6

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