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Write a slope-intercept equation for a line with the given characteristics.\newlinem=8.5m=-8.5, yy-intercept (0,45)(0,\frac{4}{5})

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Q. Write a slope-intercept equation for a line with the given characteristics.\newlinem=8.5m=-8.5, yy-intercept (0,45)(0,\frac{4}{5})
  1. Linear Equation Form: The slope-intercept form of a linear equation is given by y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Given Slope: We are given the slope m=8.5m = -8.5. This will be the coefficient of xx in our equation.
  3. Given Y-Intercept: We are also given the y-intercept as the point (0,45)(0, \frac{4}{5}). This means when x=0x = 0, y=45y = \frac{4}{5}. Therefore, b=45b = \frac{4}{5}.
  4. Final Equation: Substitute the given slope mm and y-intercept bb into the slope-intercept form of the equation to get the final equation.y=8.5x+45y = -8.5x + \frac{4}{5}

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