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Woo Jin is solving the following equation for x. 7-4x=sqrt(x+3) His first few steps are given below. {:[(7-4x)^(2)=(sqrt(x+3))^(2)],[49-56 x+16x^(2)=x+3]:} Is it necessary for Woo Jin to check his answers for extraneous solutions? Choose 1 answer: (A) Yes (B) No

Woo Jin is solving the following equation for x x .\newline7−4x=x+3 7-4 x=\sqrt{x+3} \newlineHis first few steps are given below.\newline(7−4x)2=(x+3)249−56x+16x2=x+3 \begin{aligned} (7-4 x)^{2} & =(\sqrt{x+3})^{2} \\ 49-56 x+16 x^{2} & =x+3 \end{aligned} \newlineIs it necessary for Woo Jin to check his answers for extraneous solutions?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No \mathrm{No}

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Q. Woo Jin is solving the following equation for x x .\newline7−4x=x+3 7-4 x=\sqrt{x+3} \newlineHis first few steps are given below.\newline(7−4x)2=(x+3)249−56x+16x2=x+3 \begin{aligned} (7-4 x)^{2} & =(\sqrt{x+3})^{2} \\ 49-56 x+16 x^{2} & =x+3 \end{aligned} \newlineIs it necessary for Woo Jin to check his answers for extraneous solutions?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No \mathrm{No}
  1. Identify Extraneous Solutions: Woo Jin is solving an equation that involves a square root. When both sides of an equation are squared, as Woo Jin has done, there is a possibility that extraneous solutions may be introduced. These are solutions that fit the squared form of the equation but do not satisfy the original equation. Therefore, it is necessary to check for extraneous solutions.

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