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Which of the $t$ -values satisfy the following inequality? $8>3+ \frac{t}{4}$

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Solutions to inequalities

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Q. Which of the

t

-values satisfy the following inequality?

8>3+ \frac{t}{4}

Isolate term with t: Isolate the term containing t. $\newline$ $8 > 3 + \frac{t}{4}$ $\newline$ Subtract $3$ from both sides to get the $t$ term by itself on one side of the inequality. $\newline$ $8 - 3 > 3 + \frac{t}{4} - 3$
Subtract $3$ from both sides: Simplify both sides of the inequality. $\newline$ $5 > \frac{t}{4}$ $\newline$ Now, to solve for $t$ , multiply both sides by $4$ to get rid of the fraction. $\newline$ $4 \times 5 > 4 \times \left(\frac{t}{4}\right)$
Simplify both sides: Perform the multiplication on both sides. $\newline$ $20 > t$ $\newline$ This means that $t$ must be less than $20$ to satisfy the inequality.

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