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Which of the following is equivalent to 
log(a)*log_(a)(5) ?
Choose 1 answer:
(A) 
log(a)
(B) 
log(5)
(c) 
log(5a)
(D) 
log_(a)(5a)

Which of the following is equivalent to log(a)loga(5) \log (a) \cdot \log _{a}(5) ?\newlineChoose 11 answer:\newline(A) log(a) \log (a) \newline(B) log(5) \log (5) \newline(C) log(5a) \log (5 a) \newline(D) loga(5a) \log _{a}(5 a)

Full solution

Q. Which of the following is equivalent to log(a)loga(5) \log (a) \cdot \log _{a}(5) ?\newlineChoose 11 answer:\newline(A) log(a) \log (a) \newline(B) log(5) \log (5) \newline(C) log(5a) \log (5 a) \newline(D) loga(5a) \log _{a}(5 a)
  1. Understanding the expression: Understand the expression log(a)loga(5)\log(a)\cdot\log_{a}(5).\newlineThe expression consists of two logarithms being multiplied together: log(a)\log(a), which is the common logarithm of aa, and loga(5)\log_{a}(5), which is the logarithm base aa of 55.
  2. Recognizing applicable logarithm properties: Recognize the properties of logarithms that might apply.\newlineThe multiplication of two logarithms does not directly correspond to any of the basic logarithm properties (product, quotient, or power rules). However, we can interpret loga(5)\log_{a}(5) as the power to which we must raise aa to get 55.
  3. Applying the definition of logarithm base aa of 55: Apply the definition of the logarithm base aa of 55.\newlineBy definition, loga(5)=x\log_{a}(5) = x means that ax=5a^x = 5. Therefore, loga(5)\log_{a}(5) is the exponent xx.
  4. Substituting the definition back into the original expression: Substitute the definition back into the original expression.\newlineSince loga(5)\log_{a}(5) is the exponent xx that makes ax=5a^x = 5, we can rewrite the expression as log(a)x\log(a) \cdot x.
  5. Recognizing the expression cannot be further simplified: Recognize that the expression log(a)x\log(a) \cdot x does not simplify further using common logarithm properties.\newlineThe expression log(a)x\log(a) \cdot x is already in its simplest form, given that xx is the exponent that satisfies ax=5a^x = 5. There is no property of logarithms that allows us to combine a logarithm and an exponent in this way.
  6. Matching the expression to the given options: Match the expression to the given options.\newlineNone of the options (A)log(a)(A) \log(a), (B)log(5)(B) \log(5), (C)log(5a)(C) \log(5a), or (D)loga(5a)(D) \log_{a}(5a) are equivalent to the expression log(a)x\log(a) \cdot x. Therefore, none of the options are equivalent to the original expression log(a)loga(5)\log(a)\cdot\log_{a}(5).

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