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Which of the following is an equation of the line in the
xy - plane with
x intercept
-(2)/(7) and
y-intercept
(8)/(7) ?
Choose 1 answer:
(A)
7y-28 x=8
(B)
7y+28 x=8
(c)
-7y+28 x=8
(D)
-7y-28 x=8

Which of the following is an equation of the line in the $x y$ - plane with $x$ intercept $-\frac{2}{7}$ and $y$ -intercept $\frac{8}{7}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $7 y-28 x=8$ $\newline$ (B) $7 y+28 x=8$ $\newline$ (c) $-7 y+28 x=8$ $\newline$ (D) $-7 y-28 x=8$

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Reflections of functions

Full solution

Q. Which of the following is an equation of the line in the

x y

- plane with

x

intercept

-\frac{2}{7}

and

y

-intercept

\frac{8}{7}

?

\newline

Choose

1

answer:

\newline

(A)

7 y-28 x=8

\newline

(B)

7 y+28 x=8

\newline

(c)

-7 y+28 x=8

\newline

(D)

-7 y-28 x=8

Find Slope Using Intercepts: To find the equation of the line, we can use the slope-intercept form $y = mx + b$ , where $m$ is the slope and $b$ is the $y$ -intercept. First, we need to find the slope using the $x$ -intercept and $y$ -intercept.
Calculate Slope: The slope $m$ is calculated by the change in $y$ over the change in $x$ . Since the $x$ -intercept is at $x = -\left(\frac{2}{7}\right)$ (which corresponds to $y = 0$ ) and the $y$ -intercept is at $y = \left(\frac{8}{7}\right)$ (which corresponds to $x = 0$ ), the slope $m$ is $y$ $0$ .
Use Slope-Intercept Form: Now we have the slope $m = 4$ and the y-intercept $b = \frac{8}{7}$ . We can plug these into the slope-intercept form to get $y = 4x + \frac{8}{7}$ .
Convert to Standard Form: To convert this into standard form $Ax + By = C$ , we multiply everything by $7$ to get rid of the fraction: $7y = 28x + 8$ .
Rearrange Equation: Rearrange the equation to get it into standard form: $-28x + 7y = 8$ .

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Question

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Tess tried to solve the differential equation

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\newline

\frac{d y}{d x}=2 x y-6 x

\newline

1

\quad \frac{d y}{d x}=(y-3) 2 x

\newline

2

\quad \int \frac{1}{y-3} d y=\int 2 x d x

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3

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5

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\newline

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\newline

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\newline

4

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\newline

7

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Aditya tried to solve the differential equation

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\newline

\frac{d y}{d x}=6 x-30

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2

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of the following expressions represents the distance between the sandbag and the target?

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Question

f(x) = -(x+1)(x+7)

\newline

The function represents a parabola in the

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f

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\newline

1

\newline

f(x) = -(x+4)^{2}+9

\newline

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f(x)

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