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Which formulas represent linear relationships? Select all that apply.\newlineMulti-select Choices:\newline(A)the area of a circle, A=πr2A = \pi r^2\newline(B)the perimeter of a regular hexagon, P=6sP = 6s\newline(C)the volume of a sphere, V=43πr3V = \frac{4}{3} \pi r^3\newline(D)the perimeter of an isosceles right triangle, P=(2+2)sP = (2 + \sqrt{2})s

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Q. Which formulas represent linear relationships? Select all that apply.\newlineMulti-select Choices:\newline(A)the area of a circle, A=πr2A = \pi r^2\newline(B)the perimeter of a regular hexagon, P=6sP = 6s\newline(C)the volume of a sphere, V=43πr3V = \frac{4}{3} \pi r^3\newline(D)the perimeter of an isosceles right triangle, P=(2+2)sP = (2 + \sqrt{2})s
  1. Linear Relationship Definition: Linear relationships are represented by equations where the dependent variable changes at a constant rate with respect to the independent variable. The equation should be of the first degree.
  2. Choice (A) Area of Circle: Choice (A) A=πr2A = \pi r^2 describes the area of a circle, which depends on the square of the radius (r2)(r^2). This is not a linear relationship because it involves a square term.
  3. Choice (B) Perimeter of Hexagon: Choice (B) P=6sP = 6s describes the perimeter of a regular hexagon, where PP changes linearly with each change in side length ss. This is a linear relationship because it involves only the first power of ss.
  4. Choice (C) Volume of Sphere: Choice (C) V=43πr3V = \frac{4}{3} \pi r^3 describes the volume of a sphere, which depends on the cube of the radius (r3)(r^3). This is not a linear relationship because it involves a cube term.
  5. Choice (D) Perimeter of Triangle: Choice (D) P=(2+2)sP = (2 + \sqrt{2})s describes the perimeter of an isosceles right triangle, where PP changes linearly with each change in side length ss. This is a linear relationship because it involves only the first power of ss.

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