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Which expression is equivalent to


3root(4)(2^(8)y^(16))*2root(6)(2^(6)y^(12))*root(8)(2^(24)y^(16))" where "y > 0?

66. Which expression is equivalent to\newline328y164226y126224y168 where y>0? 3 \sqrt[4]{2^{8} y^{16}} \cdot 2 \sqrt[6]{2^{6} y^{12}} \cdot \sqrt[8]{2^{24} y^{16}} \text { where } y>0 ?

Full solution

Q. 66. Which expression is equivalent to\newline328y164226y126224y168 where y>0? 3 \sqrt[4]{2^{8} y^{16}} \cdot 2 \sqrt[6]{2^{6} y^{12}} \cdot \sqrt[8]{2^{24} y^{16}} \text { where } y>0 ?
  1. Simplify Terms: Step 11: Simplify each term separately.\newlineWe start by simplifying each root term:\newline- For the first term, 328y1643\sqrt[4]{2^8y^{16}}, simplify the powers under the root:\newline 28=22×42^8 = 2^{2 \times 4} and y16=y4×4y^{16} = y^{4 \times 4},\newline so 328y164=3×22y4=12y43\sqrt[4]{2^8y^{16}} = 3 \times 2^2y^4 = 12y^4.
  2. Simplify Second Term: Step 22: Simplify the second term.\newline- For the second term, 226y1262\sqrt[6]{2^6y^{12}}, simplify the powers under the root:\newline 26=21×62^6 = 2^{1 \times 6} and y12=y2×6y^{12} = y^{2 \times 6},\newline so 226y126=2×21y2=4y22\sqrt[6]{2^6y^{12}} = 2 \times 2^1y^2 = 4y^2.
  3. Simplify Third Term: Step 33: Simplify the third term.\newline- For the third term, 224y168\sqrt[8]{2^{24}y^{16}}, simplify the powers under the root:\newline 224=23×82^{24} = 2^{3 \times 8} and y16=y2×8y^{16} = y^{2 \times 8},\newline so 224y168=23y2=8y2\sqrt[8]{2^{24}y^{16}} = 2^3y^2 = 8y^2.
  4. Multiply Simplified Terms: Step 44: Multiply all simplified terms together.\newline- Multiply 12y412y^4, 4y24y^2, and 8y28y^2 together:\newline 12y4×4y2×8y2=12×4×8×y4+2+2=384y812y^4 \times 4y^2 \times 8y^2 = 12 \times 4 \times 8 \times y^{4+2+2} = 384y^8.

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