Q. 6. Which expression is equivalent to3428y16⋅2626y12⋅8224y16 where y>0?
Simplify Terms: Step 1: Simplify each term separately.We start by simplifying each root term:- For the first term, 3428y16, simplify the powers under the root:28=22×4 and y16=y4×4, so 3428y16=3×22y4=12y4.
Simplify Second Term: Step 2: Simplify the second term.- For the second term, 2626y12, simplify the powers under the root:26=21×6 and y12=y2×6, so 2626y12=2×21y2=4y2.
Simplify Third Term: Step 3: Simplify the third term.- For the third term, 8224y16, simplify the powers under the root:224=23×8 and y16=y2×8, so 8224y16=23y2=8y2.
Multiply Simplified Terms: Step 4: Multiply all simplified terms together.- Multiply 12y4, 4y2, and 8y2 together:12y4×4y2×8y2=12×4×8×y4+2+2=384y8.
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