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Which equation has the solution x=7 ? 7x+3=52 5x-7=68 6x+2=47 2x-4=-10

Which equation has the solution x=7 x=7 ?\newline7x+3=52 7 x+3=52 \newline5x−7=68 5 x-7=68 \newline6x+2=47 6 x+2=47 \newline2x−4=−10 2 x-4=-10

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Solve a system of equations in three variables using eliminationright chevron icon

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Q. Which equation has the solution x=7 x=7 ?\newline7x+3=52 7 x+3=52 \newline5x−7=68 5 x-7=68 \newline6x+2=47 6 x+2=47 \newline2x−4=−10 2 x-4=-10
  1. Substitute x=7x=7: To find out which equation has the solution x=7x=7, we need to substitute x=7x=7 into each equation and see which one results in a true statement.\newlineLet's start with the first equation: 7x+3=527x+3=52.\newlineSubstitute x=7x=7 into the equation: 7(7)+3=527(7) + 3 = 52.\newlineCalculate: 49+3=5249 + 3 = 52.\newlineCheck if the statement is true: 52=5252 = 52.
  2. Check first equation: Now let's check the second equation: 5x−7=685x-7=68. Substitute x=7x=7 into the equation: 5(7)−7=685(7) - 7 = 68. Calculate: 35−7=6835 - 7 = 68. Check if the statement is true: 28≠6828 \neq 68. This equation does not have the solution x=7x=7.
  3. Check second equation: Next, let's check the third equation: 6x+2=476x+2=47. Substitute x=7x=7 into the equation: 6(7)+2=476(7) + 2 = 47. Calculate: 42+2=4742 + 2 = 47. Check if the statement is true: 44≠4744 \neq 47. This equation does not have the solution x=7x=7.
  4. Check third equation: Finally, let's check the fourth equation: 2x−4=−102x-4=-10. Substitute x=7x=7 into the equation: 2(7)−4=−102(7) - 4 = -10. Calculate: 14−4=−1014 - 4 = -10. Check if the statement is true: 10≠−1010 \neq -10. This equation does not have the solution x=7x=7.

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