Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which equation has the solution x=7 ? 5x+1=-36 6x+9=81 5x-2=30 4x+9=37

Which equation has the solution x=7 x=7 ?\newline5x+1=−36 5 x+1=-36 \newline6x+9=81 6 x+9=81 \newline5x−2=30 5 x-2=30 \newline4x+9=37 4 x+9=37

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Precalculusright chevron icon
Solve a system of equations in three variables using eliminationright chevron icon

Full solution

Q. Which equation has the solution x=7 x=7 ?\newline5x+1=−36 5 x+1=-36 \newline6x+9=81 6 x+9=81 \newline5x−2=30 5 x-2=30 \newline4x+9=37 4 x+9=37
  1. Identify Equation: We need to find which equation has x=7x=7 as its solution. To do this, we will substitute x=7x=7 into each equation and see which one holds true.
  2. Check First Equation: Substitute x=7x=7 into the first equation 5x+1=−365x+1=-36.
    5(7)+1=−365(7) + 1 = -36
    35+1=−3635 + 1 = -36
    36=−3636 = -36
    This is not true, so the first equation does not have x=7x=7 as its solution.
  3. Check Second Equation: Substitute x=7x=7 into the second equation 6x+9=816x+9=81.
    6(7)+9=816(7) + 9 = 81
    42+9=8142 + 9 = 81
    51=8151 = 81
    This is not true, so the second equation does not have x=7x=7 as its solution.
  4. Check Third Equation: Substitute x=7x=7 into the third equation 5x−2=305x-2=30.5(7)−2=305(7) - 2 = 3035−2=3035 - 2 = 3033=3033 = 30This is not true, so the third equation does not have x=7x=7 as its solution.
  5. Check Fourth Equation: Substitute x=7x=7 into the fourth equation 4x+9=374x+9=37.
    4(7)+9=374(7) + 9 = 37
    28+9=3728 + 9 = 37
    37=3737 = 37
    This is true, so the fourth equation has x=7x=7 as its solution.

More problems from Solve a system of equations in three variables using elimination

Question
Solve using substitution. 5x−2y=−7 5x - 2y = -7 x=−5 x = -5 (_,_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Is (1,1)(1,1) a solution to this system of equations? \newline4x+10y=144x + 10y = 14\newlinex+6y=7x + 6y = 7\newlineChoices:\newline(A) yes \newline(B) no
Get tutor helpright-arrow

Posted 2 months ago

Question
Which describes the system of equations below?\newliney=–3x+9y = –3x + 9 \newliney=–3x+9y = –3x + 9 \newlineChoices:\newline(A) consistent and independent\text{(A) consistent and independent} \newline(B) consistent and dependent\text{(B) consistent and dependent} \newline(C) inconsistent\text{(C) inconsistent}
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve using elimination. \newline7x−8y=−17 7x - 8y = -17 \newline −7x+3y=2 -7x + 3y = 2 \newline (____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve. \newlinex=−2 x = -2 \newline−2x+2y=−8 -2x + 2y = -8 \newline(____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineAt a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases 33 hot dog meals and 33 hamburger meals, paying a total of $36\$36. Mr. Hogan buys 11 hot dog meal and 33 hamburger meals, spending $26\$26 in all. How much do the meals cost?\newlineHot dog meals cost $\$_______ each, and hamburger meals cost $\$________ each.
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations by substitution.\newline−3x−y−3z=−11-3x - y - 3z = -11\newlinez=5z = 5\newlinex−y+3z=19x - y + 3z = 19\newline(____.____,____)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations by elimination.\newlinex−3y−2z=10 x - 3y - 2z = 10 \newline3x+2y+2z=14 3x + 2y + 2z = 14 \newline2x−3y−2z=16 2x - 3y - 2z = 16 \newline(_,_,_)(\_,\_,\_)
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve the system of equations.\newliney=x2+36x+3 y = x^2 + 36x + 3 \newliney=22x−37 y = 22x - 37 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_)(\_,\_)\newline(_,_)(\_,\_)
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve the system of equations.\newliney=−x−24 y = -x - 24 \newlinex2+y2=488 x^2 + y^2 = 488 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_) (\_,\_) \newline(_,_) (\_,\_)
Get tutor helpright-arrow

Posted 2 months ago

View all (6)