Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
AI tutor
Welcome to Bytelearn!
Let’s check out your problem:
Which equation has the solution
x
=
3
x=3
x
=
3
?
\newline
1
1
1
\newline
1
1
1
\newline
3
3
3
\newline
4
4
4
\newline
3
x
+
2
=
11
3 x+2=11
3
x
+
2
=
11
\newline
5
x
+
1
=
10
5 x+1=10
5
x
+
1
=
10
\newline
2
x
−
5
=
15
2 x-5=15
2
x
−
5
=
15
\newline
4
x
−
3
=
12
4 x-3=12
4
x
−
3
=
12
View step-by-step help
Home
Math Problems
Algebra 2
Solve a system of equations in three variables using elimination
Full solution
Q.
Which equation has the solution
x
=
3
x=3
x
=
3
?
\newline
1
1
1
\newline
1
1
1
\newline
3
3
3
\newline
4
4
4
\newline
3
x
+
2
=
11
3 x+2=11
3
x
+
2
=
11
\newline
5
x
+
1
=
10
5 x+1=10
5
x
+
1
=
10
\newline
2
x
−
5
=
15
2 x-5=15
2
x
−
5
=
15
\newline
4
x
−
3
=
12
4 x-3=12
4
x
−
3
=
12
Plug
x
=
3
x=3
x
=
3
:
Plug
x
=
3
x=3
x
=
3
into the first equation
3
x
+
2
=
11
3x+2=11
3
x
+
2
=
11
.
\newline
3
(
3
)
+
2
=
11
3(3) + 2 = 11
3
(
3
)
+
2
=
11
\newline
9
+
2
=
11
9 + 2 = 11
9
+
2
=
11
\newline
11
=
11
11 = 11
11
=
11
Equation
1
1
1
:
Plug
x
=
3
x=3
x
=
3
into the second equation
5
x
+
1
=
10
5x+1=10
5
x
+
1
=
10
.
\newline
5
(
3
)
+
1
=
10
5(3) + 1 = 10
5
(
3
)
+
1
=
10
\newline
15
+
1
=
16
15 + 1 = 16
15
+
1
=
16
\newline
16
≠
10
16 \neq 10
16
=
10
Equation
2
2
2
:
Plug
x
=
3
x=3
x
=
3
into the third equation
2
x
−
5
=
15
2x-5=15
2
x
−
5
=
15
.
\newline
2
(
3
)
−
5
=
15
2(3) - 5 = 15
2
(
3
)
−
5
=
15
\newline
6
−
5
=
1
6 - 5 = 1
6
−
5
=
1
\newline
1
≠
15
1 \neq 15
1
=
15
Equation
3
3
3
:
Plug
x
=
3
x=3
x
=
3
into the fourth equation
4
x
−
3
=
12
4x-3=12
4
x
−
3
=
12
.
\newline
4
(
3
)
−
3
=
12
4(3) - 3 = 12
4
(
3
)
−
3
=
12
\newline
12
−
3
=
9
12 - 3 = 9
12
−
3
=
9
\newline
9
≠
12
9 \neq 12
9
=
12
More problems from Solve a system of equations in three variables using elimination
Question
Solve using substitution.
5
x
−
2
y
=
−
7
5x - 2y = -7
5
x
−
2
y
=
−
7
x
=
−
5
x = -5
x
=
−
5
(_,_)
Get tutor help
Posted 3 months ago
Question
Is
(
1
,
1
)
(1,1)
(
1
,
1
)
a solution to this system of equations?
\newline
4
x
+
10
y
=
14
4x + 10y = 14
4
x
+
10
y
=
14
\newline
x
+
6
y
=
7
x + 6y = 7
x
+
6
y
=
7
\newline
Choices:
\newline
(A) yes
\newline
(B) no
Get tutor help
Posted 3 months ago
Question
Which describes the system of equations below?
\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
–3
x
+
9
\newline
y
=
–
3
x
+
9
y = –3x + 9
y
=
–3
x
+
9
\newline
Choices:
\newline
(A) consistent and independent
\text{(A) consistent and independent}
(A) consistent and independent
\newline
(B) consistent and dependent
\text{(B) consistent and dependent}
(B) consistent and dependent
\newline
(C) inconsistent
\text{(C) inconsistent}
(C) inconsistent
Get tutor help
Posted 3 months ago
Question
Solve using elimination.
\newline
7
x
−
8
y
=
−
17
7x - 8y = -17
7
x
−
8
y
=
−
17
\newline
−
7
x
+
3
y
=
2
-7x + 3y = 2
−
7
x
+
3
y
=
2
\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
Get tutor help
Posted 3 months ago
Question
Solve.
\newline
x
=
−
2
x = -2
x
=
−
2
\newline
−
2
x
+
2
y
=
−
8
-2x + 2y = -8
−
2
x
+
2
y
=
−
8
\newline
(
_
_
_
_
,
_
_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
,
____
)
Get tutor help
Posted 3 months ago
Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
\newline
At a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases
3
3
3
hot dog meals and
3
3
3
hamburger meals, paying a total of
$
36
\$36
$36
. Mr. Hogan buys
1
1
1
hot dog meal and
3
3
3
hamburger meals, spending
$
26
\$26
$26
in all. How much do the meals cost?
\newline
Hot dog meals cost
$
\$
$
_______ each, and hamburger meals cost
$
\$
$
________ each.
Get tutor help
Posted 3 months ago
Question
Solve the system of equations by substitution.
\newline
−
3
x
−
y
−
3
z
=
−
11
-3x - y - 3z = -11
−
3
x
−
y
−
3
z
=
−
11
\newline
z
=
5
z = 5
z
=
5
\newline
x
−
y
+
3
z
=
19
x - y + 3z = 19
x
−
y
+
3
z
=
19
\newline
(____.____,____)
Get tutor help
Posted 3 months ago
Question
Solve the system of equations by elimination.
\newline
x
−
3
y
−
2
z
=
10
x - 3y - 2z = 10
x
−
3
y
−
2
z
=
10
\newline
3
x
+
2
y
+
2
z
=
14
3x + 2y + 2z = 14
3
x
+
2
y
+
2
z
=
14
\newline
2
x
−
3
y
−
2
z
=
16
2x - 3y - 2z = 16
2
x
−
3
y
−
2
z
=
16
\newline
(
_
,
_
,
_
)
(\_,\_,\_)
(
_
,
_
,
_
)
Get tutor help
Posted 2 months ago
Question
Solve the system of equations.
\newline
y
=
x
2
+
36
x
+
3
y = x^2 + 36x + 3
y
=
x
2
+
36
x
+
3
\newline
y
=
22
x
−
37
y = 22x - 37
y
=
22
x
−
37
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
Get tutor help
Posted 2 months ago
Question
Solve the system of equations.
\newline
y
=
−
x
−
24
y = -x - 24
y
=
−
x
−
24
\newline
x
2
+
y
2
=
488
x^2 + y^2 = 488
x
2
+
y
2
=
488
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
Get tutor help
Posted 3 months ago