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When a number is increased by $48\%$ , the result is $92$ . What is the original number to the nearest tenth?

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Find the total given a part and a percent

Full solution

Q. When a number is increased by

48\%

, the result is

92

. What is the original number to the nearest tenth?

Denote original number: Let's denote the original number as $x$ . When $x$ is increased by $48\%$ , it becomes $x + 0.48x$ , which is equal to $1.48x$ . We are given that $1.48x$ equals $92$ . To find the original number $x$ , we need to divide $92$ by $1.48$ . $\newline$ Calculation: $x$ $0$
Calculate $x$ : Now let's perform the division to find the value of $x$ . $\newline$ Calculation: $x \approx 62.1622$ $\newline$ To find the original number to the nearest tenth, we round this value to one decimal place. $\newline$ Calculation: $x \approx 62.2$

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